Answer:
apart from using the hoc to predict the college students gpa, some other variables can be used
1. the students intelligent quotient
2. ability to remember
3. study time
4. gym practice
Step-by-step explanation:
<u>1. the students intelligent quotient</u>
<u>gpa</u><u> </u>has a positive relationship with iq. they are both directly related. The more the iq of a a student, the greater is his ability to understand and have a good gpa. the slope will therefore be positive and be in an upward direction.
2. <u>ability to remember</u>
the gpa of students who have a good ability to remember but do not have a good grasp of the subject may not be high. the slope would be in a slightly upward direction
3. <u>study time</u>
gpa and practice have a positive relationship. the more a student studies, the more likelihood exists of having a better gpa. the slope would be upward bound.
4. <u>gym</u><u> </u><u>practice</u>
gpa and gym practice are not related so the slope would be in a downward direction.
when interpreting the direction of relationship after carrying out such an analysis, it is useful to watch out for the accompanying signs of the variables. if the sign of the beta coefficient is positive then a positive relationship with the dependent variable exists.
Answer:
The mass of the Blue whale is 200 times the mass of the cow
Step-by-step explanation:
Given
Mass of Cow = 9 * 10² kg
Mass of Blue Whale = 1.8 * 10⁵ kg
Required
Determine the relationship between both weights
Represent the mass of the cow with C and the mass of the whale with B






Divide the bigger weight by the smaller weight



Multiply both sides by C



<em>From the expression above, it can be concluded that the mass of the Blue whale is 200 times the mass of the cow</em>
central angle of a circle whose radius is 8 cm and intercepted arc length is 7.2 cm is 0.9 radians
Step-by-step explanation:
We need to find the central angle of a circle whose radius is 8 cm and intercepted arc length is 7.2 cm.
arc length l== 7.2 cm
radius =r= 8 cm
central angle=Ф = ?
The formula used is:

Putting values:

So, central angle of a circle whose radius is 8 cm and intercepted arc length is 7.2 cm is 0.9 radians
Keywords: central angle of circle
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Answer:
<em>When 60 beats are heard, Tom hits 15 snare drums, Sam hits 6 kettle drums, and Matt hits 5 bass drums.</em>
Step-by-step explanation:
The Least Common Multiple ( LCM )
The LCM of two integers a,b is the smallest positive integer that is evenly divisible by both a and b.
For example:
LCM(20,8)=40
LCM(35,18)=630
Since Tom, Sam, and Matt are counting drum beats at their own frequency, we must find the least common multiple of all their beats frequency.
Find the LCM of 4,10,12. Follow this procedure:
List prime factorization of all the numbers:
4 = 2*2
10 = 2*5
12 = 2*2*3
Multiply all the factors the greatest times they occur:
LCM=2*2*3*5=60
Thus, when 60 beats are heard, Tom hits 15 snare drums, Sam hits 6 kettle drums, and Matt hits 5 bass drums.
Answer:
1
The probability is 
2
The probability is 
Step-by-step explanation:
From the question we are told that
The population mean is 
The standard deviation is 
The sample size is 
Generally the standard error for the sample mean
is mathematically evaluated as

substituting values


Apply central limit theorem[CLT] we have that
![P(\= X < 33) = [z < \frac{33 - \mu }{\sigma_{\= x}} ]](https://tex.z-dn.net/?f=P%28%5C%3D%20X%20%3C%2033%29%20%3D%20%20%5Bz%20%3C%20%20%5Cfrac%7B33%20-%20%20%5Cmu%20%7D%7B%5Csigma_%7B%5C%3D%20x%7D%7D%20%5D)
substituting values
![P(\= X < 33) = [z < \frac{33 - 28.29 }{4.48} ]](https://tex.z-dn.net/?f=P%28%5C%3D%20X%20%3C%2033%29%20%3D%20%20%5Bz%20%3C%20%20%5Cfrac%7B33%20-%20%2028.29%20%7D%7B4.48%7D%20%5D)
![P(\= X < 33) = [z < 1.05 ]](https://tex.z-dn.net/?f=P%28%5C%3D%20X%20%3C%2033%29%20%3D%20%20%5Bz%20%3C%20%201.05%20%5D)
From the z-table we have that

For the second question
Apply central limit theorem[CLT] we have that
![P(\= X > 30 ) = [z > \frac{30 - \mu }{\sigma_{\= x}} ]](https://tex.z-dn.net/?f=P%28%5C%3D%20X%20%3E%2030%20%29%20%3D%20%20%5Bz%20%3E%20%20%5Cfrac%7B30%20-%20%20%5Cmu%20%7D%7B%5Csigma_%7B%5C%3D%20x%7D%7D%20%5D)
substituting values
![P(\= X < 33) = [z > \frac{30 - 28.29 }{4.48} ]](https://tex.z-dn.net/?f=P%28%5C%3D%20X%20%3C%2033%29%20%3D%20%20%5Bz%20%3E%20%20%5Cfrac%7B30%20-%20%2028.29%20%7D%7B4.48%7D%20%5D)
From the z-table we have that

Thus

