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butalik [34]
1 year ago
7

You ask 150 people about their pets. The results show that 9/25 of the people own a dog. Of the people who own a dog. 1/6 of the

m also own a cat. How many people own a dog and a cat?
Mathematics
1 answer:
pav-90 [236]1 year ago
6 0

Answer: 9

Step-by-step explanation:

In order to find the people out of the 150, we first multiply 9/25 and 150 together. This will give us the people who DO own a dog. This brings us to 54.

Now, if we multiply 54 by 1/6 we get the answer of 9, because 1/6 of the dog owners own a cat as well. We have now reached the desired amount.

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If 24= 2f+3f+f, find f​
VashaNatasha [74]

Answer:

6f = 24

f = 4

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
A long time ago Dulani found an island shaped like a triangle with three straight shores of length 3 km 4 km and 5 km.He said no
VikaD [51]
To find the area of his exclusion zone you would need to understand that a triangle with dimensions of 3, 4, and 5 represent a right triangle.

This means the exclusion zone would be applied to the base and the height of the triangular space.

You would add 2 km to the 3 km, and 2 km to the 4 km to create a new height of 5 km and a new base of 6 km.

Please see the attached picture to understand this.

You will find the area of the total space created by the new triangle and subtract the space represented by the original triangle to find the area of the exclusion zone.

(1/2 x 6 x 5) - (1/2 x 4 x 3)
15 km² -6 km² equals 9 km².

The exclusion space is 9 km².

5 0
2 years ago
In an analysis of healthcare data, ages have been rounded to the nearest multiple of 5 years. The difference between the true ag
Mars2501 [29]

Answer:

The approximate probability that the mean of the rounded ages within 0.25 years of the mean of the true ages is P=0.766.

Step-by-step explanation:

We have a uniform distribution from which we are taking a sample of size n=48. We have to determine the sampling distribution and calculate the probability of getting a sample within 0.25 years of the mean of the true ages.

The mean of the uniform distribution is:

\mu=\dfrac{Max+Min}{2}=\dfrac{2.5+(-2.5)}{2}=0

The standard deviation of the uniform distribution is:

\sigma=\dfrac{Max-Min}{\sqrt{12}}=\dfrac{2.5-(-2.5)}{\sqrt{12}}=\dfrac{5}{3.46}=1.44

The sampling distribution can be approximated as a normal distribution with the following parameters:

\mu_s=\mu=0\\\\\sigma_s=\dfrac{\sigma}{\sqrt{n}}=\dfrac{1.44}{\sqrt{48}}=\dfrac{1.44}{6.93}=0.21

We can now calculate the probability that the sample mean falls within 0.25 from the mean of the true ages using the z-score:

z=\dfrac{X-\mu}{\sigma}=\dfrac{0.25-0}{0.21}=\dfrac{0.25}{0.21}=1.19\\\\\\P(|X_s-\mu|

7 0
2 years ago
What are the solutions of the compound inequality 2d + 3 ≤ –11 or 3d – 9 > 15?
pentagon [3]

Step-by-step explanation:

1.

2d + 3 \leqslant  - 11 \\ 2d \leqslant  - 11 - 3 \\ 2d \leqslant  - 14 \\  \frac{2d}{2}  \leqslant  \frac{ - 14}{2}  \\ d \leqslant - 7

2.

3d - 9 > 15 \\ 3d > 15 + 9 \\ 3d > 24 \\  \frac{3d}{3}  >  \frac{24}{3}  \\ d = 8

Welcome

3 0
2 years ago
An afterschool program offers tutoring for different subjects during the last month, a teacher recorded the number of students w
Tasya [4]
I’m not exactly sure, but I think you have to find the percentage of the people in the math tutoring compared to the total. You can do this by finding the total number of people, which would be 200, and then dividing 40 by 200, to get 20%, so 20% of the total students participated in the math tutoring. So, using this logic, 20% of 100 is 20, so 20 students would go to math tutoring if there was a total of 100 students
6 0
2 years ago
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