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kirill115 [55]
2 years ago
10

What is the value of the 2s in 42,256

Mathematics
2 answers:
Ne4ueva [31]2 years ago
6 0
The value of the 2 in the number is thousands. Hope that's what you're looking for.
Anna71 [15]2 years ago
4 0
2,000 and 200 are the values of the 2s in 42256

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Lin multiplies 7/8 times a number. The product is less than 7/8. Which could be Lin’s number?
RSB [31]

Answer:

So, the number that Lin multiplied by 7/8 MUST be less than 1. This is evident, as any positive number multiplied by a number less than 1 will decrease, doesn't matter if its a negative or positive number.

Step-by-step explanation:

3 0
2 years ago
A parabola is represented by the equation y = x2 + 6x − 17. The x-intercepts of the parabola are____ and_____ . The y-intercept
kramer

Answer:

2.8, 8.8, and -17 respectively.

Step-by-step explanation:

We need to find roots of the equation.

4 0
2 years ago
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Events M and N are independent events. In this scenario, if P(M) = 0.46 and P(M and N) = 0.138, then P(N) = .
Oksi-84 [34.3K]

Answer:

P(N)=0.3

Step-by-step explanation:

Given: P(M)= 0.46, P(M and N)=0.138

Using P(M) ×P(N)= P(M and N)

⇒0.46×P(N)= 0.138

⇒P(N)= \frac{0.138}{0.46}

⇒P(N)=0.3

7 0
2 years ago
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Consider a limousine that gets m(v)= (120 - 2v) / 5 miles per gallon at speed v , whose chauffeur is paid $15/hour, and gas cost
DENIUS [597]

Answer:

(17.5 / 120 - 2v) + (15 / v)

Step-by-step explanation:

Given : m(v)= (120 - 2v) / 5 miles per gallon at speed v ,

chauffeur is paid $15/hour

gas cost = $3.5/gallon.

Gasoline cost per mile :

Cost per gallon = $3.5

Cost per gallon * 1/(m(v))

$3.5 * 1 / (120 - 2v) / 5

$3.5 * 5 / 120 - 2 v

= 17.5 / 120 - 2v

Time = distance / speed

Chauffeur cost = 15 per hour / v

Hence ;

Total cost :

Cost of gasoline + Cost of chauffeur

(17.5 / 120 - 2v) + (15 / v)

8 0
2 years ago
Using the quadratic formula to solve 4x2 – 3x + 9 = 2x + 1, what are the values of x? StartRoot 1 plus-or-minus StartRoot 159 En
castortr0y [4]

For this case we have that a quadratic equation is of the form:

ax ^ 2 + bx + c = 0

The roots are given by:

x = \frac {-b \pm \sqrt {b ^ 2-4 (a) (c)}} {2 (a)}

We have the following equation:

4x ^ 2-3x + 9 = 2x + 1\\4x ^ 2-3x-2x + 9-1 = 0\\4x ^ 2-5x + 8 = 0

We look for the roots:

x = \frac {- (- 5) \pm \sqrt {(- 5) ^ 2-4 (4) (8)}} {2 (4)}\\x = \frac {5 \pm \sqrt {25-128}} {8}\\x = \frac {5 \pm \sqrt {-103}} {8}

We have to:

i ^ 2 = -1

So:

x = \frac {5 \pm \sqrt {103i ^ 2}} {8}\\x = \frac {5 \pm i \sqrt {103}} {8}

We have two imaginary roots:

x_ {1} = \frac {5 \ + i \sqrt {103}} {8}\\x_ {2} = \frac {5 \ -i \sqrt {103}} {8}

Answer:

x_ {1} = \frac {5 \ + i \sqrt {103}} {8}\\x_ {2} = \frac {5 \ -i \sqrt {103}} {8}

8 0
2 years ago
Read 2 more answers
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