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2 years ago

What is the value of the 2s in 42,256

Mathematics

2 answers:

Ne4ueva [31]2 years ago

6 0

The value of the 2 in the number is thousands. Hope that's what you're looking for.

Anna71 [15]2 years ago

4 0

2,000 and 200 are the values of the 2s in 42256

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Jen and Ariel are reading a 400 page novel for their literature class. Jen decides to read 100 pages the first day and 50 pages

Furkat [3]

Answer:

Option B is the correct answer.

Step-by-step explanation:

Jen decides to read 100 pages the first day and 50 pages each day thereafter.

Number of pages read by Jen per day = 50

Number of pages read by Jen on first day = 100

Ariel's progress on reading the book is represented by the linear function y = 40x + 80, where y is the total number of pages read after x days.

Number of pages read by Ariel per day = 40

Number of pages read by Ariel on first day = 40 + 80 = 120

Option A:

Jen reads 20 pages per day more than Ariel

Wrong

Option B:

Ariel reads 10 pages per day less than Jen.

Correct

Option C:

Ariel read 20 pages less the first day than Jen read.

Wrong

Option D:

The reading rate each day for Jen and Ariel is the same.

Wrong

Option B is the correct answer.

6 0

2 years ago

Read 2 more answers

Problem 5 (4+4+4=12) We roll two fair 6-sided dice. Each one of the 36 possible outcomes is assumed to be equally likely. 1) Fin

tekilochka [14]

Answer:

$p(b) = \frac{1}{6}$

$p(k) = \frac{1}{3}$

$P(a) = \frac{1}{3}$

Step-by-step explanation:

Generally when two fair 6-sided dice is rolled the doubles are

(1 1) , ( 2 2) , (3 3) , (4 4) , ( 5 5 ), (6 6)

The total outcome of doubles is N = 6

The total outcome of the rolling the two fair 6-sided dice is

n = 36

Generally the probability that doubles (i.e., having an equal number on the two dice) were rolled is mathematically evaluated as

$p(b) = \frac{N}{n}$

$p(b) = \frac{6}{36}$

$p(b) = \frac{1}{6}$

Generally when two fair 6-sided dice is rolled the outcome whose sum is 4 or less is

(1, 1), (1, 2), (1, 3), (2, 1), (2, 2), (3, 1)

Looking at this outcome we see that there are two doubles present

The conditional probability that doubles were rolled is mathematically represented as

$p(k) = \frac{2}{6}$

$p(k) = \frac{1}{3}$

Generally when two fair 6-sided dice is rolled the number of outcomes that would land on different numbers is L = 30

And the number of outcomes that at least one die is a 1 is W = 10

The conditional probability that at least one die is a 1 is mathematically represented as

$P(a) = \frac{W}{L}$

=> $P(a) = \frac{10}{30}$

=> $P(a) = \frac{1}{3}$

3 0

2 years ago

Sue scored a total of 35 points in two games.she scored 6 times as many points in the second game than in the first.how many mor

kirill115 [55]

Okay,
Both games are: 35
First game: ?
Second game: 6 more than the first.
So,
first we subtract 6 from 35.
35 - 6 = 29
Divide by 2.
49 divided by 2 = 14.5
Add the 6 point= 14.5 + 6 = 20.5
To make sure add.
First game: 14.5
Second game:20.5
14.5 + 20.5 = 35

3 0

2 years ago

A metal disc of 12cm in diameter and 5cm thick is melted down and cast into a cylindrical bar of diameter 5cm .How long is the b

Trava [24]

Answer:

d bar

Step-by-step explanation:

3 0

2 years ago

Jackson goes to the gym 0, 2, or 3 days per week, depending on work demands. The expected value of the number of days per week t

valina [46]

For a probability distribution the expected value is the summation of product of probabilities with their respective data values. Let x be the probability that Jackson goes gym for 2 days and y be the probability that he goes gym for 3 days.

For the given case we have following values and their probabilities:

0 : 0.1

2 : x

3 : y

So the expected value will be = 0(0.1) + 2(x) + 3(y)

Expected value is given to be 2.05. So we can write the equation as:

2x + 3y = 2.05 (Equation 1)

Also for a probability distribution, the sum of probabilities must always equal to 1. So we can set up the second equation as:

0.1 + x + y = 1

x + y = 0.9 (Equation 2)

From Equation 2 we can write the value of x to be x = 0.9 - y. Using this value in equation 1, we get:

2(0.9 - y) + 3y = 2.05

1.8 - 2y + 3y = 2.05

1.8 + y = 2.05

y = 0.25

Using the value of y in equation 2 we get value of x to be 0.65

Therefore we can conclude that:

The probability that Jackson goes to gym for 2 days is 0.65 and the probability that he goes to gym for 3 days is 0.25

6 0

2 years ago

Read 2 more answers