For a 30-60-90 triangle the sides always have the same relationship
Short leg = a
Long leg = a√3
Hypotenuse = 2a
BC is the short leg of ∆ABC
Given BC = 2
BC = a
Therefor
a = 2
AB = 2a = 4
AC = a√3 = 2√3
For ∆ACD
As above AC = 2√3
Since AC is the hypotenuse of ∆ACD
2a = 2√3
a = √3
CD = a = √3
AD = a√3 = 3
For ∆BCD
As above
BC = 2
CD = √3
Since BC is the hypotenuse of ∆BCD
2a = 2
a = 1
DB = a = 1
3 x 10 to the sixth power
3 x 10 to the fifth power
7 x 10 to the fourth power
6 x 10 to the first power
I might be wrong though. If so, sorry!
Answer:
LAST OPTION: 
Step-by-step explanation:
1. Subtract 
from both sides of the equation:
2. Since 
:
3. Now can complete the square. Add 
to both sides of the equation:
4. Simplifying:
5. Solve for "x":
6. The solution set is:
Answer:
C
Step-by-step explanation:
The equation of a line is given by
and
slope (m) is given by:
Where (x_1,y_1) are the first set of point in the line and (x_2,y_2) is the second set of point
Let's take 2 points arbitrarily. (0,0) & (25,20)
Let's plug it and find the equation:
Now
C is the correct answer.
