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Elenna [48]
2 years ago
14

The coefficient of determination: a. cannot be negative b. is the square root of the coefficient of correlation c. can be negati

ve or positive d. is the same as the coefficient of correlation
Mathematics
1 answer:
patriot [66]2 years ago
5 0

Answer:

Correct statement: (a) and (b).

Step-by-step explanation:

R-squared is a statistical quantity that measures, just how near the values are to the fitted regression line. It is also known as the coefficient of determination.

The coefficient of determination is the squared value of the correlation coefficient.

That is,

R^{2}=(r(X, Y))^{2}

The correlation coefficient between two variables is the measure of the strength and direction of the relationship between two variables.

Its values ranges from -1.00 to +1.00.

Although <em>r</em> can be negative but R² is always positive, since square of a negative number is also positive.

So the correct statements are:

a. cannot be negative

b. is the square root of the coefficient of correlation

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A sled is being held at rest on a slope that makes an angle theta with the horizontal. After the sled is released, it slides a d
Alenkasestr [34]

Answer:

μ =  Sin θ * d₁ / (d₂ - Cos θ*d₁)

d₂ = (d₁*Sin θ) / μ

Step-by-step explanation:

a) We apply The work-energy theorem

W = ΔE

W = - Ff*d

Ff = μ*N = μ*m*g

<em>Distance 1:</em>

- Ff*d₁ = Ef - Ei

⇒  - (μ*m*g*Cos θ)*d₁ = (Kf+Uf) - (Ki+Ui) = (Kf+0) - (0+Ui) = Kf - Ui

Kf = 0.5*m*vf² = 0.5*m*v²

Ui = m*g*h = m*g*d₁*Sin θ

then

- (μ*m*g*Cos θ)*d₁ = 0.5*m*v² - m*g*d₁*Sin θ  

⇒   - μ*g*Cos θ*d₁ = 0.5*v² - g*d₁*Sin θ   <em>(I)</em>

 

<em>Distance 2:</em>

<em />

- Ff*d₂ = Ef - Ei

⇒  - (μ*m*g)*d₂ = (0+0) - (Ki+0) = - Ki

Ki = 0.5*m*vi² = 0.5*m*v²

then

- (μ*m*g)*d₂ = - 0.5*m*v²

⇒   μ*g*d₂ = 0.5*v²     <em>(II)</em>

<em />

<em>If we apply (I) + (II)</em>

- μ*g*Cos θ*d₁ = 0.5*v² - g*d₁*Sin θ

μ*g*d₂ = 0.5*v²

 ⇒ μ*g (d₂ - Cos θ*d₁) = v² - g*d₁*Sin θ   <em>  (III)</em>

Applying the equation (for the distance 1) we get v:

vf² = vi² + 2*a*d = 0² + 2*(g*Sin θ)*d₁   ⇒   vf² = 2*g*Sin θ*d₁ = v²

then (from the equation <em>III</em>) we get

μ*g (d₂ - Cos θ*d₁) = 2*g*Sin θ*d₁ - g*d₁*Sin θ

⇒  μ (d₂ - Cos θ*d₁) = Sin θ * d₁

⇒   μ =  Sin θ * d₁ / (d₂ - Cos θ*d₁)

b)

If μ is a known value

d₂ = ?

We apply The work-energy theorem again

W = ΔK   ⇒   - Ff*d₂ = Kf - Ki

Ff = μ*m*g

Kf = 0

Ki = 0.5*m*v² = 0.5*m*2*g*Sin θ*d₁ = m*g*Sin θ*d₁

Finally

- μ*m*g*d₂ = 0 - m*g*Sin θ*d₁   ⇒   d₂ = Sin θ*d₁ / μ

3 0
2 years ago
Explain the steps for dividing decimals. Write three or four sentences.
ryzh [129]

Answer:

1.First Move the decimal point in the divisor and dividend.

2.Place a decimal point in the quotient (the answer) directly above where the decimal point now appears in the dividend.

3.Divide as usual, being careful to line up the quotient properly so that the decimal point falls into place.

Step-by-step explanation:

I got it from google tbh

8 0
2 years ago
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A family dines in a popular franchise restaurant. They plan to use a coupon that will give them a discount of 10% off of their t
Alecsey [184]
See you add 990 then diced by 54 and then you’ll get your answer
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2 years ago
What is the value of x which proves that the runways are parallel? What is the measure of the larger angle? (evidently the answe
romanna [79]
I feel like the answer is C
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A function that models the profit for a new pet-monitoring system shows that there is no profit made until the price reaches
____ [38]

Answer:

The graph that best fits this model of profit and price per unit is attached to this solution.

Step-by-step explanation:

A couple of graphs are missing from the question. According to the full question as obtained online, there are a number of graph options, and we are expected to pick the best option. I would not add all the other graphs to limit the chances of deletion due to violating community guidelines.

The function is to model the profits of a new pet-monitoring system, so, if the profits are y and x is the price per unit, y = f(x)

The profits vary as the price per unit varies, there is no profit made until the price reaches

$95 per unit, a maximum profit at a price of $140 per unit, and no profit at a price over $185 per unit.

This description of the curve shows that y is negative at values of x less than $95, then the profits increase when x varies between $95 and $140. The profits reach a maximum at $140 and then the profits start to decline as x increases again, the profits go to 0 at x = $185.

This description shows that the function is a quadratic function with a graph that is n-shaped, peaking at x=185 and the graph crosses the x-axis at x=95 and x=185.

The most fitting graph for this model is attached to this solution provided.

From the graph, all the descriptions above are evident.

Hope this Helps!!!

6 0
2 years ago
Read 2 more answers
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