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2 years ago

Your neighbor has a square shaped pool with side lengths of 3a5 what is the area of the pool

Mathematics

2 answers:

Anvisha [2.4K]2 years ago

7 0

If a square-shaped pool with side lengths are 3a^5 then find the area of the pool

solution:

A = (3a^5) x (3a^5)

= 9a^5+5

= 9a^10

The area of the square-shaped pool are 9a^10 based on the given side length which is 3a^5

iris [78.8K]2 years ago

5 0

Answer:

Area of the pool is $9a^{10}$ .

Step-by-step explanation:

If my neighbor has a pool in square shape with the side lengths = $3a^{5}$

We know area of a square is represented by

Area = (side)²

By putting measure of side in the given formula,

Area = $(3a^{5}\times 3a^{5})$

= $9(a^{5})^{2}$

= $9a^{(5+5)}$ [Since $a^{b}\times a^{b}=a^{b+b}$ ]

= $9a^{10}$

Therefore, area of the pool is $9a^{10}$ .

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Mario eats twice as many as Yolanda. If Yolanda eats 6 walnuts every day, how many walnuts does Mario eat in a week?

stepladder [879]

let

x-------> walnuts that Mario eats in a week

y-------> walnuts that Yolanda eats in a week

we know that

x=2y-------> equation 1

y=6*7-------> y=42 walnuts

substitute the value of y in equation 1

x=2*42-----> x=84 walnuts

therefore

the answer is

Mario eat in a week 84 walnuts

8 0

2 years ago

Joe receives an average of 780 emails in his personal account and 760 emails in his work account each month. After changing his

Semmy [17]

Answer:

702 emails

Step-by-step explanation:

<h2>This problem bothers on depreciation of value, in this context it is Joe's email that has depreciated by 10%.</h2>

Given data

Average personal emails received monthly = $780 emails$

Average work emails received monthly $= 760 emails$

We are required to solve for the new amount of emails Joe will be receiving after changing his address, to find this value we need to solve for the depreciation of his personal mails.

After solving for the depreciation , we then need to subtract the depreciation from the initial number of mails to get the new number of mails.

let us solve for 10% depreciation.

$depreciation= \frac{10}{100} *780\\depreciation=0.1*780= 78 emails$

The new number of mails

$= initial number of mail- depreciation\\ =780-78= 702 emails$

Joe will be receiving an average of 702 emails in his personal account monthly

7 0

1 year ago

Find a line that lies entirely in the set defined by the equation x2 + y2 − z2 = 1.

RUDIKE [14]

Answer:

$x=1\,,\,y=t\,,\,z=t$

Step-by-step explanation:

A line is a one-dimensional figure that has no thickness and extends infinitely in both directions.

A line segment is a line that has two end-points and a ray is a line that has one end-point.

Given equation is $x^2+y^2-z^2=1$

To find : a line that lies entirely in the set defined by the given equation.

Solution:

Take $x=1\,,\,y=t\,,\,z=t$

Check:

$L.H.S=1^2+t^2-t^2=1+0=1=R.H.S$

Therefore, $x=1\,,\,y=t\,,\,z=t$ satisfy the given equation.

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2 years ago

Suppose a research paper states that the distribution of the daily sea-ice advance/retreat from each sensor is similar and is ap

Luda [366]

Answer:

The value of the parameter is λ is 0.03553357

Step-by-step explanation:

Consider the provided function.

$f(x) = 0.5\lambda e^{-\lambda |x|}$ for −∞ < x < ∞.

It is given that standard deviation is given as 39.8 km.

Now we need to calculate the value of parameter λ.

The general formula for the probability density function of the double exponential distribution is: $f(x)=\frac{e^{-|\frac{x-\mu}{\beta}|}}{2\beta}$

Where μ is the location parameter and β is the scale parameter.

Compare the provided equation with the above formula we get.

$\lambda=\frac{1}{\beta}$ and μ = 0.

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$S.D=\sqrt{2} \beta\\\beta=\frac{39.8}{\sqrt{2}}\\\beta=28.1424$

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3 0

2 years ago

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icang [17]

| x - 8| = 3

x - 8 = 3 - (x - 8) = 3
x = 3 + 8 -x + 8 = 3
x = 11 -x = 3 - 8
-x = - 5
x = 5

Minimum : 5% Maximum : 11% if u need them added it is 16%

5 0

1 year ago

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