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Korvikt [17]
1 year ago
6

A new car is purchased for 20700 dollars. The value of the car depreciates are 11% per year. What will the value of the car be,

to the nearest cent, after 11 years?
Mathematics
1 answer:
ASHA 777 [7]1 year ago
5 0

Answer: $5,744.61

Step-by-step explanation:

year 1 = -2,277

year 2 = -2026.53

year 3 = -1803.61

year 4 = -1605.21

year 5 = -1428.64

year 6 = -1271.49

year 7 = -1131.62

year 8 = -1007.17

year 9 = -896.36

year 10 = -797.76

year 11 = -710

you are subtracting 11% from each year.

You might be interested in
the probability that Jenya receives spam email is 4%.if she receives 520 email in a week about how much will be spam
wariber [46]
520*.04=20.8, or closer to 21 spam emails.
6 0
1 year ago
Carissa counts by 5s from 32 to 62. Which number does carissa count?
Anna35 [415]

Answer:

32, 37, 42, 47, 52, 57, 62.

Step-by-step explanation:

It is given that Carissa counts by 5s from 32 to 62.

It means, we have to add 5 in the number to get the next number.

Add 5 in 32.

32+5=37

Now, add 5 in 37.

37+5=42

Similarly, continue the process.

42+5=47

47+5=52

52+5=57

57+5=62

Therefore, the numbers counted by carissa are 32, 37, 42, 47, 52, 57, 62.

4 0
2 years ago
a car rental service rently purchased all new vehicles .to help cover the cost ,rental rates have to increase 26% from the norma
ruslelena [56]

Answer:

The new rate should be $56.67 per day

Step-by-step explanation:

Proportion states that the two fractions or ratios are equal.

As per the statement:

Normal rate per day = $45

To find the new rate:

Let new rate be x per day

By definition of proportion:

\frac{126}{100} = \frac{x}{45}

By cross multiply we have;

100x = 126 \times 45

Divide both sides by 100 we get;

x = \frac{126 \times 45}{100}

Simplify:

x = $56.7

Therefore, the new rate should be $56.7 per day




5 0
2 years ago
Suppose the time required for an auto shop to do a tune-up is normally distributed, with a mean of 102 minutes and a standard de
hammer [34]

Answer:

Step-by-step explanation:

Suppose the time required for an auto shop to do a tune-up is normally distributed, we would apply the formula for normal distribution which is expressed as

z = (x - u)/s

Where

x = points scored by students

u = mean time

s = standard deviation

From the information given,

u = 102 minutes

s = 18 minutes

1) We want to find the probability that a tune-up will take more than 2hrs. It is expressed as

P(x > 120 minutes) = 1 - P(x ≤ 120)

For x = 120

z = (120 - 102)/18 = 1

Looking at the normal distribution table, the probability corresponding to the z score is 0.8413

P(x > 120) = 1 - 0.8413 = 0.1587

2) We want to find the probability that a tune-up will take lesser than 66 minutes. It is expressed as

P(x < 66 minutes)

For x = 66

z = (66 - 102)/18 = - 2

Looking at the normal distribution table, the probability corresponding to the z score is 0.02275

P(x < 66 minutes) = 0.02275

4 0
2 years ago
Uma urna contém 10 bolas identificadas pelas letras A, B, ..., J. Uma bola é extraída ao acaso da urna e sua letra é observada.
arlik [135]

Answer:

a) Probability that a letter of the drawn ball is vowel = (3/10) = 0.30

b) Probability that a letter of the drawn ball is consonant = (7/10) = 0.70

a) Probabilidade de uma letra da bola sacada ser vogal = (3/10) = 0.30

b) Probabilidade de uma letra da bola sacada ser consoante = (7/10) = 0,70

Step-by-step explanation:

English Translation

A ballot box contains 10 balls identified by the letters A, B, ..., J. A ball is drawn at random from the ballot box and its letter is observed. (Make the sample space and all events explicit). What is the probability that a letter of the drawn ball is: a) Vowel b) Consonant

Solution

The 10 balls are identified by A, B, C, D, E, F, G, H, I and J

Note that the probability of an event is given as the number of elements in that event divided by the number of elements in the sample space.

a) Probability of drawing a ball that has a vowel letter = P(v)

P(v) = n(v) ÷ n(S)

n(v) = Number of balls with vowel letters = 3 (that is, A, E and I)

n(S) = Total number of balls = 10

P(v) = (3/10) = 0.30

b) Probability of drawing a ball that has a consonant letter = P(c)

P(c) = n(c) ÷ n(S)

n(c) = Number of balls with consonant letters = 7 (that is, B, C, D, F, G, H and J)

n(S) = Total number of balls = 10

P(c) = (7/10) = 0.70

In Portugese/Em português

As 10 bolas são identificadas por A, B, C, D, E, F, G, H, I e J.

Observe que a probabilidade de um evento é fornecida como o número de elementos nesse evento dividido pelo número de elementos no espaço de amostra.

a) Probabilidade de desenhar uma bola com uma letra de vogal = P (v)

P (v) = n (v) ÷ n (S)

n (v) = Número de bolas com letras de vogal = 3 (ou seja, A, E e I)

n (S) = Número total de bolas = 10

P (v) = (3/10) = 0,30

b) Probabilidade de desenhar uma bola com uma letra consoante = P (c)

P (c) = n (c) ÷ n (S)

n (c) = Número de bolas com letras consoantes = 7 (ou seja, B, C, D, F, G, H e J)

n (S) = Número total de bolas = 10

P (c) = (7/10) = 0,70

Hope this Helps!!!!

Espero que isto ajude!!!!

3 0
1 year ago
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