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madreJ [45]
2 years ago
15

7/8 of a rectangle is colored red. Damien cuts this red part into a number of pieces so that each piece is 1/24 of the whole rec

tangle. Find the number of red pieces Damien has.
Mathematics
1 answer:
Degger [83]2 years ago
7 0

Answer: Damien has 21 red pieces

Step-by-step explanation:

First, 7/8 of the rectangle is coloured red.

Then, the 7/8 was cut into a size 1/24 of the rectangle each.

That consequently means that 24 of those pieces will form the whole shape.

Since red covers 7/8 of the rectangle, the number of red pieces invariably becomes

⅞ × 24 pieces, which is equal to 21 pieces

Therefore, Damien has cut the red part of the rectangle into 21 pieces

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A sphere has a radius of 16 in. Which statements about the sphere are true? Check all that apply.
Wewaii [24]

Answer:

  • The sphere has a diameter of 32 in. CORRECT: the diameter of a sphere doubles its radio, so if the radio equals 16,the diameter measures the double, in this case, 32.
  • The radius' lenght is one half the length of the diameter. CORRECT: , by definition, the diameter is the maximum distance between two opposite points on the surface of the sphere, and its lenght equals twice the radius because the radius is the distance between the center of the sphere and any point of the frontier of the sphere (then, one colud imagine that the distance between two opposite points in a sphere can be united by two radius, or a diameter).
  • The volume (V) of a sphere can be calculated as \frac{4\pi r^3}{3}, where r is the radio. In this case, the volume of the sphere will be \frac{4\pi\times16^3}{3}=\frac{4\pi\times4096}{3}, which is also equal to \frac{16384\times\pi}{3}.

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2 years ago
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Sum of positive roots of the equation (x2 - 12x + 35) (x2 + 10x + 24) = 504 is
Digiron [165]

Answer:

(3)11

Step-by-step explanation:

We are given that

(x^2-12x+35)(x^2+10x+24)=504

We have to find the sum of positive roots of the equation.

x^2(x^2+10x+24)-12x(x^2+10x+24)+35(x^2+10x+24)=504

x^4+10x^3+24x^2-12x^3-120x^2-288x+35x^2+350x+840=504

x^4-2x^3-61x^2+62x+840-504=0

x^4-2x^3-61x^2+62x+336=0

Factor of 336

2,3,4,6,8,7,

Let x=2

2^4-2^4-61(2^2)+62(2)+336\neq0

x=2 is not the root of equation

x=-2

(-2)^4-2(-2)^3-61(-2)^2+62(-2)+336=0

Hence x=-2 is the root of equation.

x+2 is a factor of equation.

x=3

3^4-2(3^3)-61(3^2)+62(3)+336=0

Therefore, x=3  is the root of equation.

(x+2)(x-3)(x^2-x-56)=0

(x+2)(x-3)(x^2-8x+7x-56)=0

(x+2)(x-3)(x(x-8)+7(x-8))=0

(x+2)(x-3)(x-8)(x+7)=0

x-8=0\implies x=8

x+7=0\implies x=-7

Positive roots are 3 and 8

Sum of positive roots=3+8=11

Option (3) is true.

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