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MrRissso [65]
2 years ago
13

What is the perimeter of quadrilateral DOBC

Mathematics
1 answer:
rosijanka [135]2 years ago
7 0
No one see the quadrilateral
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What is a simplified form of -(14x)^0y^-7z
GenaCL600 [577]
Anything to the power of 0 is one.

Therefore we have:

(1)(y^-7z)

Which simplifies to:

y^-7z
3 0
2 years ago
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Tamara and Clyde got different answers when dividing 2x4 + 7x3 – 18x2 + 11x – 2 by 2x2 – 3x + 1. Analyze their individual work.
Umnica [9.8K]

The statements and their individual answers are not provided in the question. However, please check the explanation given below for the equation.

Step-by-step explanation:

  • The equation given is \frac{2x^{4} + 7x^{3} + 18x^{2} + 11x -2}{2x^{2} - 3x + 1 }
  • Divide the leading term of the dividend by the leading term of the divisor: \frac{2x^{4} }{2x^{2} }  = x^{2}
  •  Multiply it by the divisor: x^{2} ({2x^{2} -3x +1) = 2x^{4} - 3x^{3} + x^{2}
  • Subtract the dividend from the obtained result: (2x^{4} + 7x^{3} + 18x^{2} + 11x - 2) - (2x^{4} - 3x^{3} + x^{2} ) = (10x^{3} + 17x^{2} + 11x -2)
  • Divide the leading term of the obtained remainder by the leading term of the divisor: \frac{10x^{3}}{2x^{2} }  = 5x
  • Multiply it by the divisor: 5x (2x^{2} - 3x + 1) = 10x^{3} - 15x^{2} + 5x
  • Subtract the remainder from the obtained result: (10x^{3} + 17x^{2} + 11x -2) - (10x^{3} - 15x^{2} + 5x) = (32x^{2} + 6x - 2)
  • Divide the leading term of the obtained remainder by the leading term of the divisor: \frac{32x^{2} }{2x^{2} } = 16
  • Multiply it by the divisor: 16 (2x^{2} - 3x +1) = 32x^{2} - 48x +16
  • Subtract the remainder from the obtained result: (32x^{2} + 6x - 2) - (32x^{2} - 48x +16) = 54x - 18
  • Since the degree of the remainder is less than the degree of the divisor, then we are done.
  • Therefore,  \frac{2x^{4} + 7x^{3} + 18x^{2} + 11x -2}{2x^{2} - 3x + 1 } = (x^{2} + 5x +16 + \frac{54x - 18}{2x^{2}  - 3x +1})
7 0
2 years ago
Read 2 more answers
(2.5 points) The probability that an airplane accident which is due to structural failure is diagnosed correctly is 0.85 and the
Nikitich [7]

Answer: 0.51

Step-by-step explanation:

This is a conditional probability. The first event is the airplane accident being caused by structural failure. The probability of it being due to structural failure is 0.3 and the probability of it not being due to structural failure is 0.7. The second event involves the diagnosis of the event. If a plane fails due to structural failure, the probability that it will be diagnosed and the results will say it was due to structural failure is 0.85, and the probability that the diagnosis is unable to identify that it was because of a structural failure is 0.15. If the plane were to fail as a result of some other reason aside structural failure, the probability that the diagnosis will show that it was as a result of structural failure is 0.35 and the probability of the diagnosis showing that is is not as a result of structural failure is 0.65. To find the probability that an airplane failed due to structural failure given that it was diagnosed that it failed due to some malfunction, this is the equation;

p = (probability of plane failing and diagnosis reporting that the failure was due to structural failure)/ (probability of diagnosis reporting that failure was due to structural failure)

p = (0.3*0.85)/((0.3*0.85) + (0.7*0.35))

p = 0.51

4 0
2 years ago
Jillian said StartRoot 25 EndRoot is irrational because it is a square root. Why is she incorrect? Jillian is incorrect because
8_murik_8 [283]

Answer:

Jillian is incorrect because square roots of perfect squares are rational.

Step-by-step explanation:

√25 = √(5²) = 5 - rational

25 is perfect square.

6 0
2 years ago
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The heights of students in a class are normally distributed with mean 55 inches and standard deviation 5 inches. Use the Empiric
maks197457 [2]

Answer:  c)[50,60]

Step-by-step explanation:

The Empirical rule says that , About 68% of the population lies with the one standard deviation from the mean (For normally distribution).

We are given that , The heights of students in a class are normally distributed with mean 55 inches and standard deviation 5 inches.

Then by Empirical rule, about 68% of the heights of students lies between one standard deviation from mean.

i.e. about 68% of the heights of students lies between \text{Mean}\pm\text{Standard deviation}

i.e. about 68% of the heights of students lies between 55\pm5

Here, 55\pm5=(55-5, 55+5)=(50,60)

i.e.  The required interval that contains the middle 68% of the heights. = [50,60]

Hence, the correct answer is c) (50,60)

4 0
2 years ago
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