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Vlada [557]
2 years ago
15

Choose all lengths that are equal to 3 yards 16 inches.

Mathematics
1 answer:
Feliz [49]2 years ago
7 0

we are given

length =3 yards and 16 inches

now, we can change it in inches

we know that

1 yard =36 inches

so, we get

length =3*36 inches and 16 inches

length=124 inches

now, we will check each option

option-A:

we can see that this is also 124 inches

so, this is TRUE

option-B:

4 yd 4 in

we can change into inches

we know that

1 yard =36 inches

4 yd 4 in=4*36 inches +4 inch

4 yd 4 in=144 in

this is not equal to 124 in

so, this is FALSE

option-C:

3 yd 1 1/2 in

we know that

1 yard =36 inches

3 yd 1 1/2 in = 3*36+\frac{11}{2}

3 yd 1 1/2 in = 113.5 in

this is not same as 124 in

so, this is FALSE

option-D:

2 yd 52 in

we know that

1 yard =36 inches

2 yd 52 in =2*36+52

2 yd 52 in =124 in

so, this is same

so, this is TRUE

option-E:

10 ft 4 in

we know that

1 feet =12 inches

so,

10 ft 4 in=12*10 +4 in

10 ft 4 in=124 in

this is same

so, this is TRUE

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The scores on a statistics test had a mean of 81 and a standard deviation of 9. One student was absent on the test day and his s
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Answer: E) Mean will decrease, standard deviation will decrease

Step-by-step explanation:

Initial mean = 81

Initial standard deviation = 9

New score = 78

Taking a look at the initial mean(averahe) score, which is 81 and the new score to be added to the initial scores, the initial average is greater than the new score. Hence, this will result in a decrease in the new mean score after adding the new score of 78.

Also, taking a look at the standard deviation which is 9, we can conclude that the variability in initial scores from the mean scores is high. However, the new score of 78 and the initial mean are very close, and tend to low variation. Hence, adding the new score will lead to a decrease in variability and hence a decrease in the value of standard deviation.

8 0
2 years ago
A random sample of 160 car purchases are selected and categorized by age. The results are listed below. The age distribution of
seraphim [82]

Answer:

The claim that all ages have purchase rates proportional to their driving rates is false.

Step-by-step explanation:

The complete question is:

A random sample of 160 car accidents are selected and categorized by the age of the driver determined to be at fault. The results are listed below. The age distribution of drivers for the given categories is 18% for the under 26 group, 39% for the 26-45 group, 31% for the 45-65 group, and 12% for the group over 65. Calculate the chi-square test statistic used to test the claim that all ages have crash rates proportional to their driving rates.

Age      >26     26-45       46-65      45<

Drivers 66    39            25          30

  A) 95.431

      B)101.324

      C)85.123

      D)75.101

Solution:

In this case we need to test whether there is sufficient evidence to warrant rejection of the claim that all ages have crash rates proportional to their driving rates.

A Chi-square test for goodness of fit will be used in this case.

The hypothesis can be defined as:

<em>H₀</em>: The observed frequencies are same as the expected frequencies.

<em>Hₐ</em>: The observed frequencies are not same as the expected frequencies.

The test statistic is given as follows:

\chi^{2}=\sum{\frac{(O-E)^{2}}{E}}

The values are computed in the table.

The test statistic value is 75.10.

The degrees of freedom of the test is:

n - 1 = 4 - 1 = 3

Compute the p-value of the test as follows:

p-value < 0.00001

*Use a Chi-square table.

p-value < 0.00001 < α = 0.05.

So, the null hypothesis will be rejected at any significance level.

Thus, there is sufficient evidence to warrant rejection of the claim that ages have crash rates proportional to their driving rates.

3 0
2 years ago
Which expression is equivalent to logw((x^2-6)^4/(cube root x^2+8))
Arturiano [62]

Answer: The expression is in the explanation.

Step-by-step explanation:

Please find the attached file for the solution.

5 0
1 year ago
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Nathan had an infection, and his doctor wanted him to take penicillin. Because Nathan’s father and paternal grandfather were all
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Let events
A=Nathan has allergy
~A=Nathan does not have allergy
T=Nathan tests positive
~T=Nathan does not test positive

We are given
P(A)=0.75  [ probability that Nathan is allergic ]
P(T|A)=0.98  [probability of testing positive given Nathan is allergic to Penicillin]

We want to calculate probability that Nathan is allergic AND tests positive
P(T n A)

From definition of conditional probability,
P(T|A)=P(T n A)/P(A)
substitute known values,
0.98 = P(T n A) / 0.75
solving for P(T n A)
P(T n A) = 0.75*0.98 = 0.735

Hope this helps!!
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12x50=600 so 60 left
15x50=750 so 60 left
so the administration fee is 60
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