The fencing line x is the height of a rectangle triangle of base = y, hypothenuse of 9 m, so we use Pythagoras theorem to solve:
hyp^2 = height^2 + base^2
9^2 = x^2 + y^2
x^2 = 81 - y^2
we can see that x is also the height of another rectangle triangle of base = 15 - y, hypothenuse of 12 m, so we use Pythagoras theorem to solve:
hyp^2 = height^2 + base^2
12^2 = x^2 + (15 - y)^2
lets expand:
144 = x^2 + 225 - 30y + y^2
substitute x^2 from the first equation in the last:
144 = 81 - y^2 + 225 - 30y + y^2
144 = 81 + 225 - 30y
30y = -144 + 81 + 225
y = 5.4 m
substitute in the fence equation:
x^2 = 81 - y^2
x^2 = 81 - 5.4^2
x = 7.2 m that is the length of the fence
Answer:
Considering all seven-digit numbers that can be created from the digits 0-9 I could deduce that you can make 100 , 700, 800 even infinite numbers
Answer:
A circle can intersect a parabola in
1. One point [ when circle just touches the parabola]
2. Two points [ When circle cuts the parabola in two distinct points. ]
3. Three points [Circle just touches at one point and cuts the parabola in two distinct points]
4. Four points [ Either parabola or circle meeting each other or crossing at four distinct points]
Answer:
x is less-than-or-equal-to 2.25 (x ≤ 2.25)
Step-by-step explanation:
We can write down the inequality that represents the weight Li can add without going over the 50 pound limit:
47.75 + x ≤ 50
If we solve for x we have:
47.75 + x ≤ 50
x ≤ 50 - 47.75
x ≤ 2.25
Therefore, the weight Li can add to the suitcase is less-than-or-equal-to 2.25