Given data, cos(A - B) = cosAcosB + sinAsinB
<span>let, A=60' and B=30' ( here the ' sign bears degree) </span>
<span>L.H.S = cos(A - B) </span>
<span>=cos (60'-30) ( using value of A and B ) </span>
<span>=cos30' </span>
<span>= sqrt3/2 </span>
<span>R.H.S= cosAcosB + sinAsinB </span>
<span>=cos60' cos30' + sin60' sin30' </span>
<span>= 1/2* sqrt3/2+ sqrt3/2*1/2 </span>
<span>= sqrt3/4 + sqrt3/4 </span>
<span>=2 sqrt3/4 </span>
<span>= sqrt3/2 </span>
<span>so L.H.S =R.H.S or cos(A - B) = cosAcosB + sinAsinB</span>
Answer:
5%
Step-by-step explanation:
Total 'halwa' made = 1
Divided into four equal portion = 1/4
Arrival of an unexpected guest = 1/5
By what percentage has each family member's share been reduced:
Change in the sharing proportion:
Previous share ratio - new sharing ratio
(1/4 - 1/5) = (5 - 4) / 20 = 1/20
That means total reduction in the sharing = 1/ 20
Since each member comes contributed equally:
Reduction in each family member's share ;
(1 / 20) ÷ 4
(1 / 20) * 1/4 = 1/ 80
Percentage reduction:
(Reduction / original share) * 100%
[(1/80) ÷ (1/4)] * 100
(1/80 * 4/1) * 100%
(1/20) * 100%
= 5%
Reduction in each family members share = 5%
Answer:
Step-by-step explanation:
Let r and j represent Riley's hours and Jace's hours, respectively. The equations could be ...
25r +30j = 460
r - j = 3
__
The solution is (r, j) = (10, 7).
5x=25 could be one.
25/x-3=2 is another.
And the last one could be x/85+7=24