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1 year ago

6

A person who had $1,000,000 gave $100 to charity. How much must a student who has $100 give to charity to give proportionally th

e same as the millionaire?

1 answer:

Oksi-84 [34.3K]1 year ago

5 0

(100 / 1,000,000) × 100% = 0.01%

x = amount of money the student has to give.

(x / 100) × 100% = 0.01%

We can cancel out the 100's

x = $0.01

The student would have to give $0.01 or 1 cent

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If the relative frequency of a train being late is 0.15 how often could you expect the train to be late in 100 days?

neonofarm [45]

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2 years ago

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2 years ago

Read 2 more answers

A coin will be flipped repeatedly until the sequence TTH (tail/tail/head) comes up. Successive flips are independent, and the co

padilas [110]

Answer:

$P = \frac{1}{3}$

Step-by-step explanation:

The calculation of the value of p minimizes is shown below:-

We will assume the probability of coming heads be p

p(H) = p

p(T) = 1 - P

Now, H and T are only outcomes of flipping a coin

So,

P(TTH) = (1 - P) = (1 - P) (1 - P) P

= (1 + P^2 - 2 P) P

= P^3 - 2P^2 + P

In order to less N,TTH

we need to increase P(TTH)

The equation will be

$\frac{d P(TTH)}{dP} = 0$

3P^2 - 4P + 1 = 0

(3P - 1) (P - 1) = 0

P = 1 and 1 ÷ 3

For P(TTH) to be maximum

$\frac{d^2 P(TTH)}{dP} < 0 for\ P\ critical\\\\\frac{d (3P^2 - 4P - 1)}{dP}$

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2 years ago

25. To produce the graph of the function y=0.5cos(0.5x), what transformations should be applied to the graph of the parent funct

soldi70 [24.7K]

Answer:

C. A horizontal stretch to produce a period of $2\pi$ and a vertical compression.

Step-by-step explanation:

We are given the parent function as $y= \cot x$

It is given that, transformations are applied to the parent function in order to obtain the function $y=0.5\cot (0.5x)$ i.e. $y=\frac{1}{2}\cot (\frac{x}{2})$

That is, we see that,

The parent function $y= \cot x$ is stretched horizontally by the factor of $\frac{1}{2}$ which gives the function $y=\cot (\frac{x}{2})$ .

Further, the function is compressed vertically by the factor of $\frac{1}{2}$ which gives the function $y=\frac{1}{2}\cot (\frac{x}{2})$ .

Now, we know,

If a function f(x) has period P, then the function cf(bx) will have period $\frac{P}{|b|}$ .

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2 years ago

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svetoff [14.1K]

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2 years ago