Ask question

Ask question

All categories

1 year ago

5

The density of air is approximately 1.225 kg/m^3 what is the volume of a soccer ball if the mass of the air it contains is 0.08

kg

1 answer:

svetoff [14.1K]1 year ago

8 0

Using the the density(D)-mass(m)-volume(V) formula $m=DV$ , we can calculate the volume $V= \frac{m}{D}= \frac{0.08}{1.225}= 0.0653 m^{3}$

You might be interested in

Elias likes to read during his summer breaks. The table below shows the number of pages in each book he read last summer and the

user100 [1]

Answer:

A.The modes differ by 40 and the ranges differ by 40.

Step-by-step explanation:

The mode of a data set is the value that occurs most often.

For the data from last summer, the value 190 is in the list twice, while all other values are only in once. This means 190 is the mode.

For the data from this summer, the value 150 is in the list twice, while all other values are only in once. This means 150 is the mode. This also means the difference in modes is 190-150 = 40.

The range is the difference between the maximum and minimum values in a data set. For last summer's data, the maximum is 220 and the minimum is 140; this gives us 220-140 = 80 for the range.

For this summer's data, the maximum is 190 and the minimum is 150; this gives us 190-150 = 40 for the range. This means the difference in ranges is 80-40 = 40.

7 0

1 year ago

Read 2 more answers

The height of a grain of a cylindrical silo is is increasing at a constant rate of 4 feet per minute At what rate is the volume

Dafna11 [192]

The answer is 2 min and 30 sec

7 0

1 year ago

Of 560 samples of seafood purchased from various kinds of food stores in different regions of a country and genetically compared

frutty [35]

Answer:

a) (0.5256,0.5944)

c) Criticism is invalid

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 560

Proportion of mislabeled = 56%

$\hat{p} = 0.56$

a) 90% Confidence interval:

$\hat{p}\pm z_{stat}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}$

$z_{critical}\text{ at}~\alpha_{0.05} = \pm 1.64$

Putting the values, we get:

$0.56\pm 1.64(\sqrt{\dfrac{0.56(1-0.56)}{560}}) = 0.56\pm 0.0344\\\\=(0.5256,0.5944)$

b) Interpretation of confidence interval:

We are 90% confident that the true proportion of all seafood in the country that is mislabeled or misidentified is between 0.5256 and 0.5944 that is 52.56% and 59.44%.

c) Validity of criticism

Conditions for validity:

$np > 10\\n(1-p)>10$

Verification:

$560\times 0.56 = 313.6>10\\560(1-0.56) = 246.4>10$

Both the conditions are satisfied. This, the criticism is invalid.

8 0

2 years ago

I tell you these facts about a mystery number, $c$: $\bullet$ $1.5 < c < 2$ $\bullet$ $c$ can be written as a fraction wit

makkiz [27]

Answer:

Possible answer: $\displaystyle c = \frac{16}{10} = \frac{8}{5} = 1.6$ .

Step-by-step explanation:

Rewrite the bounds of $c$ as fractions:

The simplest fraction for $1.5$ is $\displaystyle \frac{3}{2}$ . Write the upper bound $2$ as a fraction with the same denominator:

$\displaystyle 2 = 2 \times 1 = 2 \times \frac{2}{2} = \frac{4}{2}$ .

Hence the range for $c$ would be:

$\displaystyle \frac{3}{2} < c < \frac{4}{2}$ .

If the denominator of $c$ is also $2$ , then the range for its numerator (call it $p$ ) would be $3 < p < 4$ . Apparently, no whole number could fit into this interval. The reason is that the interval is open, and the difference between the bounds is less than $2$ .

To solve this problem, consider scaling up the denominator. To make sure that the numerator of the bounds are still whole numbers, multiply both the numerator and the denominator by a whole number (for example, 2.)

$\displaystyle \frac{3}{2} = \frac{2 \times 3}{2 \times 2} = \frac{6}{4}$ .

$\displaystyle \frac{4}{2} = \frac{2\times 4}{2 \times 2} = \frac{8}{4}$ .

At this point, the difference between the numerators is now $2$ . That allows a number ( $7$ in this case) to fit between the bounds. However, $\displaystyle \frac{1}{c} = \frac{4}{7}$ can't be written as finite decimals.

Try multiplying the numerator and the denominator by a different number.

$\displaystyle \frac{3}{2} = \frac{3 \times 3}{3 \times 2} = \frac{9}{6}$ .

$\displaystyle \frac{4}{2} = \frac{3\times 4}{3 \times 2} = \frac{12}{6}$ .

$\displaystyle \frac{3}{2} = \frac{4 \times 3}{4 \times 2} = \frac{12}{8}$ .

$\displaystyle \frac{4}{2} = \frac{4\times 4}{4 \times 2} = \frac{16}{8}$ .

$\displaystyle \frac{3}{2} = \frac{5 \times 3}{5 \times 2} = \frac{15}{10}$ .

$\displaystyle \frac{4}{2} = \frac{5\times 4}{5 \times 2} = \frac{20}{10}$ .

It is important to note that some expressions for $c$ can be simplified. For example, $\displaystyle \frac{16}{10} = \frac{2 \times 8}{2 \times 5} = \frac{8}{5}$ because of the common factor $2$ .

Apparently $\displaystyle c = \frac{16}{10} = \frac{8}{5}$ works. $c = 1.6$ while $\displaystyle \frac{1}{c} = \frac{5}{8} = 0.625$ .

8 0

2 years ago

Read 2 more answers

Draw a bar model that shows how the number of hours in March compares with the number of hours in February of this year.

gogolik [260]

Okay so first we need to find how many days are in March and February. March has 31 days and because this year was a leap year February has 29 days.

The next step is to convert days to hours.
March: 31x24=744
February: 29x24=696

Now its time to graph

8 0

2 years ago

Read 2 more answers