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Sedaia [141]
1 year ago
15

The Unique Glass Company reported sales of $24 million in 1995, and sales increased by 15% each year for the next 10 years.

Mathematics
1 answer:
Dimas [21]1 year ago
3 0

Answer:

n + 1 = 24 million x 1.15

Step-by-step explanation:

The sales is increased 15 percent, so every year 24million is multiplyed with 1.15 to get the result... so yea

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John is planning to purchase a new car that costs $15,500. On average, a new car loses 11% of its value the moment that it is dr
Levart [38]

15500 times 0.37 is 5735.

$5735

The 11% statement is extra information.

4 0
1 year ago
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A contractor has submitted bids on three state jobs: an office building, a theater, and a parking garage. State rules do not all
german

Answer:

The following are the answer to this question:

Step-by-step explanation:

In the given question the numeric value is missing which is defined in the attached file please fine it.  

Calculating the probability of the distribution for x:

\to f(x) = 0.19\  for \ x=14\\\\\to  f(x) = 0.29 \ for\ x=7\\\\\to f(x) = 0.38\  for \ x=1\\\\\to f(x)=0.14 \ for \ x=0\\

The formula for calculating the mean value:

\bold{ E(X)= x \times f(x)}

          =14 \times 0.19+7 \times 0.29+1 \times 0.38+0\times 0.14\\\\=2.66 + 2.03+0.38+ 0\\\\=5.07

\bold{E(X^2) = x^2 \times f(x)}

           =14^2 \times 0.19+7^2 \times 0.29+1^2 \times 0.38+0^2 \times 0.14 \\\\=196 \times 0.19+ 49 \times 0.29+1 \times 0.38+0 \times 0.14\\\\= 37.24+ 14.21+ 0.38+0 \\\\=51.83

use formula for calculating the Variance:

\to \bold{\text{Variance}= E(X^2) -[E(X)]^2}

                  = 51.83 - (5.07)^2\\\\= 51.83 -  25.70\\\\=26.13

calculating the value of standard deivation:

Standard Deivation (SD) = \sqrt{Variance}

                                          = \sqrt{26.13} \\\\=5.111

6 0
2 years ago
The Fibonacci sequence was first discovered during a study of rabbits. If newborn rabbits become adults in one month, each pair
Rina8888 [55]

Answer:

There will be 233 pairs of rabbits would be produced after thirteen months.

Step-by-step explanation:

Consider the provided information.

In the Fibonacci sequence we can find the next term by adding the two numbers before it.

Let us consider that we have 1 pair of newborn rabbits in first month.

Then in the second month they will fully grow.

On the next month 1 more pair of baby rabbits were born.

Next month the baby rabbits were grown and the first pair had two more baby rabbits.

Thus the sequence will look like:

Sequence: 1, 1, 2, 3

It is given that the it follows the Fibonacci sequence. Now use the above rule to generate the Fibonacci sequence.

The required Sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, 144, 233...

We need to find the number of pairs of rabbits would be produced after thirteen months.

Now from the above sequence we can find the number of rabbits produced after thirteen months.

Hence, there will be 233 pairs of rabbits would be produced after thirteen months.

4 0
2 years ago
Triangle L M Q is cut by perpendicular bisector L N. Angle N L Q is 32 degrees and angle L M N is 58 degrees.
Serga [27]

Answer:

Yes

Step-by-step explanation:

ΔMNL ≅ ΔQNL  by ASA or AAS

by ASA

Proof:

∠ LNM = ∠LNQ    =90

LN = LN   {Common}

∠MLN = ∠QLN     {LN bisects ∠ L}

By AAS

∠Q + ∠QLN + ∠LNQ = 180  {Angle sum property of triangle}

∠Q + 32 + 90 = 180

∠Q  + 122 = 180

∠Q = 180 -122 =

∠Q = 58

∠Q = ∠M

∠MNL =∠QNL = 90

LN = LN {common side}

8 0
2 years ago
The number 8/7 = 1.14285714285714 ... obviously has no exact representation in any decimal floating point system (beta = 10) wit
arlik [135]

Answer:

The answer to this question can be defined as follows:

Step-by-step explanation:

In the first point:

Yes, the Finite Floating Point Structures are considered  Where \beta = 7

\to \frac{8}{7}= (1.1)_7

\bold{= 1 \times 7^0 + 1 \times 7^{-1}}\\\\

In the second point:

There is no device with a finite floating-point since the right side is  

This equality never happens, then, with the rational numbers (\alpha_i and \beta is rational).

5 0
2 years ago
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