Given: <br> m < ark VC = m < ark VE<br> Prove: QV·KV = LV·PV

762,508 expanded form using exponents

r-ruslan [8.4K]

762,508 in expanded form using exponents is given as:

$7 \times 10^5 + 6 \times 10^4 + 2 \times 10^3 + 5 \times 10^2 +0 \times 10^1 + 8 \times 10^0$

<h3><u>Solution:</u></h3>

Given that we have to write 762, 508 in expanded form using exponents

Expanded form or expanded notation is a way of writing numbers to see the math value of individual digits

<h3><u>Write 762508 in Expanded form</u></h3>

Let us first find the place value of digits

Place value can be defined as the value represented by a digit in a number on the basis of its position in the number.

Place value of 7 = 700000

In 762508, 7 is in hundred-thousands place

Place value of 6 = 60000

In 762508, 6 is in ten-thousands place.

Place value of 2 = 2000

In 762508, 2 is in thousands place

Place value of 5 = 500

In 762508, 5 is in hundreds place

Place value of 0 = 0 x 10 = 0

In 762508, 0 is in tens place

Place value of 8 = 8

In 762508, 8 is in ones place

Therefore, the expanded form is given as:

700,000 + 60,000 + 2,000 + 500 + 0 + 8

<u><em>Using exponents we can write as,</em></u>

$7 \times 10^5 + 6 \times 10^4 + 2 \times 10^3 + 5 \times 10^2 +0 \times 10^1 + 8 \times 10^0$

6 0

2 years ago

Expand and simplify (k-3)^7

nikklg [1K]

There are a couple of ways you can solve this. You can write it out like
(K-3)(K-3)(K-3)(K-3)(K-3)(K-3)(K-3)
And pretty much use the foil method
Or you can use the binomial theorem (google it if you dont know)
The solution should be:
(K^7) - 21(k^6) + 189(k^5) - 945(k^4) + 2835(k^3) - 5103(k^2) + 5103k - 2187

3 0

2 years ago

Read 2 more answers

A pattern is made from four congruent squares

exis [7]

Answer:

more information please

Step-by-step explanation:

3 0

2 years ago

A city distributes vehicle identification stickers using a combination of letters followed by a combination of digits, each of

gayaneshka [121]

A) 672750
B) 68250
C) 2960100

Explanation
A) We have 26 letters from which to choose 4, and 10 digits from which to choose 2:
$_{26}C_4\times_{10}C_2=\frac{26!}{4!22!}\times\frac{10!}{2!8!}=14950\times45=672750$

B) We have 26 letters from which to choose 2, and 10 digits from which to choose 4:
$_{26}C_2\times_{10}C_4=\frac{26!}{2!24!}\times\frac{10!}{4!6!}=325\times210=68250$

C) We have 26 letters from which to choose 5, and 10 digits from which to choose 2:
$_{26}C_5\times_{10}C_2=\frac{26!}{5!21!}\times\frac{10!}{2!8!}=65780\times45=2960100$

5 0

2 years ago

A quality control engineer at a potato chip company tests the bag filling machine by weighing bags of potato chips. Not every ba

Ahat [919]

Answer:

$z=\frac{0.21 -0.15}{\sqrt{\frac{0.15(1-0.15)}{100}}}=1.68$