Answer:
The answer:
<W and <Z
<X and <Y
<W and <X
Step-by-step explanation:
Solving this problem actually requires us the use of the
distance formula of point to a line.
The formula is:
distance = | a x + b y + c | / sqrt (a^2 + b^2)
So we are given the equation:
y = 2 x + 4
rewriting:
<span>y – 2 x – 4 = 0 -->
a = -2, b = 1, c = -4</span>
We are also given the points:
(-4, 11) = (x, y)
Using the distance formula at points (x, y):
distance = | -2 * -4 + 1 * 11 + -4 | / sqrt [(- 2)^2 +
(1)^2]
distance = 15 / sqrt (5)
distance = 6.7
<span>So the tree is about 6.7 ft away from the zip line.</span>
Standard deviations of the four activities of the critical path are 1,2,4,2.
Standard deviation of this critical path = Sum of square root of variance of this corresponding critical path
Standard deviation of critical path 



Now we need to find the probability that the project will completed in 38 weeks given that its expected completion time is 40 weeks.
That is, we need to find P(X<38) :


Probability 
Thus the probability that the project will be completed in 38 weeks is 0.34.
Answer: 
Step-by-step explanation:
Given the following expresion provided in the exercise:

You can follow these steps in order to evaluate it when
and
:
1. You need to substitute
and
into the given expression:

2. Now you can solve the mutiplication:

3. Since
, you get:

4. You must solve the division. Divide the numerator 16 by the denominator 4. Then:

5. And finally, you must solve the addition. So, you get this result:
