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elena-s [515]
2 years ago
5

What are the solution(s) to the quadratic equation 50 - x2 = 0?

Mathematics
1 answer:
Pie2 years ago
3 0

Answer:

±5sqrt(2) = x

Step-by-step explanation:

50 - x^2 = 0

Add x^2 to each side

50 - x^2 +x^2= 0+x^2

50 = x^2

Take the square root of each side

±sqrt(50) = sqrt(x^2)

±sqrt(25*2)) = x

±sqrt(25) sqrt(2) = x

±5sqrt(2) = x

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The sum of two consecutive mile markers on the interstate is 561. Find the numbers on the markers.
vovikov84 [41]

Answer:

Step-by-step explanation:

Let x equal the first mile marker.  Then x + 1 represents the second mile marker.

Then x + (x + 1) = 561, or

2x + 1 = 561, or

2x = 560, and so x = 280

Then the first mile marker reads 280 and the second mile marker reads 281.

4 0
2 years ago
An animal shelter is feeding 24 dogs. Each dog is fed 8 ounces of dog food twice a day. How many pounds of dog food does the she
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there are 24 dogs, each one gets 8oz of dog food twice a day, so for 1 day only that'd be 16 oz, for 7 days for 1 dog only that'd be 16+16+16+16+16+16+16 oz or 112oz, just for 1 dog alone for 7 days(week).

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2 years ago
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2 years ago
Unoccupied seats on flights cause airlines to lose revenue. Suppose a large airline wants to estimate its average number of unoc
Bingel [31]

Answer:

We need a sample size of at least 719

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.95}{2} = 0.025

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.025 = 0.975, so z = 1.96

Now, find the margin of error M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

How large a sample size is required to vary population mean within 0.30 seat of the sample mean with 95% confidence interval?

This is at least n, in which n is found when M = 0.3, \sigma = 4.103. So

M = z*\frac{\sigma}{\sqrt{n}}

0.3 = 1.96*\frac{4.103}{\sqrt{n}}

0.3\sqrt{n} = 1.96*4.103

\sqrt{n} = \frac{1.96*4.103}{0.3}

(\sqrt{n})^{2} = (\frac{1.96*4.103}{0.3})^{2}

n = 718.57

Rouding up

We need a sample size of at least 719

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2 years ago
a railway car is 3.2m in diameter and 17.2m long. estimate the cost of painting the outside of the railway car, if a can of pain
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