Let the smaller number = X
Then the larger number is 3x+4 ( four more than 3 times the smaller number)
The sum of both numbers = 80
so you have X + 3X+4 = 80
Simplify the left side:
4x+4 = 80
Subtract 4 from each side:
4x = 76
Divide both sides by 4:
X = 76/4
X = 19
The smallest number is 19
The largest number is 80 - 19 = 61 ( check: 3*19 = 57+4 = 61)
The two numbers are 19 and 61
The correct answer is b=3+1/2 divided by 5+3 after that +10-3*5*3 . add the answers up and thats the solution
Answer:
The year 1996
With population of both 21600
Step-by-step explanation:
From 1990 to 2000 = 10 years
So city A grew from 12000 to 28000 that is city A had an increase of 16000 in 10 years.
While city b grew from 18000 to 24000 , that's an increase of 6000 in 10 years to.
For city A
10 years= 16000
1 year = 16000/10
1 year = 1600
For city B
10 years = 6000
1 year = 6000/10
1 year = 600
So we are to find what year the both cities had same population.
12000 + x1600 = y
18000 + x600 = y
X is the year difference
Y is the population at that year
Eliminating y gives
6000= x1000
X= 6
If x is 6
18000+3600= y
21600= y
So 6 years + 1990 = 1996
Answer:
After 2.9 years the town's tax status will change
The towns tax status change within the next 3 years
Step-by-step explanation:
The question below is
Will the towns tax status change within the next 3 years ?
Let
y -----> the population of a small town
t ----> the number of years
we have a exponential function of the form
where
a is the initial value
b is the base
In this problem
substitute
Remember that
The town's tax status will change once the population is below 6,000 people
so
The inequality that represent this situation is
Solve for t
Apply log both sides
Multiply by -1 both sides
so
After 2.9 years the town's tax status will change
therefore
The answer is
Yes, the towns tax status change within the next 3 years
2.8 millimeter to meters is .0028 but to tell you, you didn't word the question correctly at there no such thing as expanded form
