Answer:
Option a
Step-by-step explanation:
Given that all of the seniors and none of the freshmen voted for it.
Some of the juniors and some of the sophomores voted for the proposal and some voted against it.
If the proposal was to be adopted then a simple of majority of votes should have been cast.
Since all seniors voted for it, and no freshmen number of freshmen has to be less than seniors then only majority would have voted.
Regarding juniors and sophomores we assume some voted and some against thus approximately nullifying their votes.
So the correct option would be
a. There are more seniors than freshmen on the council.
Option b wrong since only some voted for it.
C is wrong because actual seniors were not given.
D is wrong because while seniors voted for sophomores voted against.
e is wrong since sophomores and freshmen nullified each other
The value of f(7) is 1.08
<em><u>Solution:</u></em>
Given that,
<em><u>The sequence is defined recursively by formula:</u></em>
where n is an integer and n is greater than 0
<em><u>Substitute n = 6 in given formula,</u></em>
<em><u>Find f(7)</u></em>
<em><u>Substitute f = 7 in given formula</u></em>
Thus the value of f(7) is 1.08
Answer:
la distancia del punto de observación A al incendio = 5.5 millas
la distancia del punto de observación B al incendio = 3.8 millas
Step-by-step explanation:
La expresión esquemática de la pregunta se puede ver en la imagen adjunta a continuación :
Del siguiente diagrama;
Usando la sine regla:
a sin 79 = 6 sin 63
a = 5.446 millas
la distancia del punto de observación A al incendio = 5.5 millas (a la décima más cercana)
b sin 79 = 6 sin 38
b = 3.7635 millas
la distancia del punto de observación B al incendio = 3.8 millas (a la décima más cercana)
Answer:
<em>11.29 grams </em><em>of strontium-90 were present in the original rock sample in 1933.</em>
Step-by-step explanation:
Strontium has a half-life of 28.8 years. Therefore,
1989 - 1933 = 56 years.
56 / 28.8 = 1.94 half-lives
Thus, the quantity of the radioisotope remaining will double for each half-life elapsed. moving backwards in time.
Therefore, moving backwards in time by 1.94 half-lives, the quantity remaining will double by 1.94 times.
Thus, the amount remaining in 1933 is
3.0 × (1.94)² = <em>11.29 grams</em>
Answer:
0.1/4-3/20=1/40-6/40=-1/8 200% of this is -1/4
Step-by-step explanation:
