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docker41 [41]
2 years ago
15

Choose the correct definition of (n/k) from below

Mathematics
2 answers:
Citrus2011 [14]2 years ago
8 0

Answer:C.  \frac{n!}{k!(n-k)!}

Step-by-step explanation:

We know that a combination is a collection of the items where the order doesn't matter. It is a way to calculate the total outcomes of an event where order of the outcomes does not matter. It is denoted by C(n,k) or (n,k) or (n/k).

The formula for the number of combinations of n things taken r at a time is given by :-

C(n,k)=(n/k)=\frac{n!}{k!(n-k)!}

Hence, C is the right option.

gizmo_the_mogwai [7]2 years ago
3 0
Answer C is correct.
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If you know that a < b, and both a and b are positive numbers, then what must be true about the relationship between the oppo
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What ever number A is, it is going to be less than whatever number B is.
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Read 2 more answers
I) Solve the equation sin2x + 3cos2x = 0 (for 0 till 360°)
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Get rid of cos2x by dividing both the values. So Sin2x/cos2x +3cos2x/cos2x.
Tan2x = 3
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Use the quadrant method and add 360 twho the two values tou get.
7 0
2 years ago
A teacher randomly chooses a two-person leadership team from a group of four qualified students. Three of the students, Sandra,
nata0808 [166]

Answer:

What is P(A), the probability that the first student is a girl? (3/4)

What is P(A), the probability that the first student is a girl? (3/4)What is P(B), the probability that the second student is a girl? (3/4)

What is P(A), the probability that the first student is a girl? (3/4)What is P(B), the probability that the second student is a girl? (3/4)What is P(A and B), the probability that the first student is a girl and the second student is a girl? (1/2)

The probability that the first student is a girl is (3/4), likewise for the 2nd 3rd and 4th it's still (3/4). The order you pick them doesn't matter.

However, once you're looking at P(A and B) then you're fixing the first position and saying if the first student is a girl what's the probability of the second student being a girl.

3 0
2 years ago
James has a total of 66 dollars in his piggy bank. He only has one dollar bills and two dollar bills in his piggy bank. If there
gavmur [86]

Answer:

32 one-dollar bills.

Step-by-step explanation:

Let <em>x </em>represent one-dollar bills and <em>y </em>represent two-dollar bills.

He has a total of 49 bills. Therefore:

x+y=49

The total amount of money James has is 66. <em>x</em> is worth one dollar, while <em>y</em> is worth two dollars. Therefore:

1x+2y=66\\x+2y=66

We have a system of equations. Solve by substitution:

x+2y=66\\x+y=49\\x=49-y\\(49-y)+2y=66\\y=17\\x=49-17=32

Therefore, James has 32 one-dollar bills and 17 two-dollar bills.

Checking:

32(1)+17(2)\stackrel{?}{=}66\\32(1)+17(2)\stackrel{\checkmark}{=}66\\\\32+17\stackrel{?}{=}49\\49\stackrel{\checkmark}{=}49

5 0
2 years ago
The letters of the word STAR are written on individual cards. If you always choose three cards and then put them back before the
Svet_ta [14]

Answer:

24

Step-by-step explanation:

There are 4 possibilities for the first card.

After that, there are 3 possibilities for the second card.

Finally, there are 2 possibilities for the third card.

The total number of permutations is 4×3×2 = 24.

Here's the list (in alphabetical order):

ARS

ART

ASR

AST

ATR

ATS

RAS

RAT

RSA

RST

RTA

RTS

SAR

SAT

SRA

SRT

STA

STR

TAR

TAS

TRA

TRS

TSA

TSR

8 0
2 years ago
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