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PSYCHO15rus [73]
2 years ago
14

Horn lengths of Texas longhorn cattle are normally distributed. The mean horn spread is 60 inches with a standard deviation of 4

.5 inches.
Calculate the range of horn lengths for the middle 68% of Texas longhorn cattle.
Mathematics
1 answer:
german2 years ago
8 0

Answer:

range is  between 55.5 to 64.5

Step-by-step explanation:

Horn lengths of Texas longhorn cattle are normally distributed. The mean horn spread is 60 inches with a standard deviation of 4.5 inches

68% is 1 standard deviation from mean

To get the range of 1 standard deviation we add and subtract standard deviation from mean

mean = 60

standard deviation = 4.5

60 - 4.5= 55.5

60+4.5 = 64.5

1 standard deviation is between 55.5 to 64.5

That is 68% range is  between 55.5 to 64.5

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Robbie Morse has a $47,500 insurance policy. The annual premium is $987.53. Robbie pays $90.00 monthly.
marin [14]

Answer:

Robbie pay in twelve months $1080 .

$92.47 more Robbie pay and 9.36 %(Approx) Robbie pay.

Step-by-step explanation:

As given

Robbie Morse has a $47,500 insurance policy.

The annual premium is $987.53.

Robbie pays $90.00 monthly.

First find out the Robbie pay in twelve months .

Robbie pay in twelve months = 12 × 90

                                                  = $ 1080

Second find out how much more does Robbie pay .

Robbie pay extra = Robbie pay in twelve months -  annual premium

                             = $ 1080 - $987.53

                             = $92.47

Therefore the $92.47 more Robbie pay .

Third find out the what percentage does Robbie pay .

 Formula

Percentage = \frac{Robbies\ pay\ more\times 100}{annual\ premium}

Robbies pay more = $92.47

Annual premium = $987.53

Put in the above

Percentage = \frac{92.47\times 100}{987.53}

Percentage = \frac{9247}{987.53}

Percentage = 9.36 % (Approx)

9.36 %(Approx) Robbie pay.


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