Answer:
124.67cm³
Step-by-step explanation:
==>Given:
Dimensions of current can:
Height (h) = 12cm
Diameter = 6cm (radius = 3cm)
Volume of current can (V1) = 339.12 cm³
Dimensions of future cans to be increased multiple of 1.11:
height = 12cm × 1.11 = 13.32 cm
radius = 3cm × 1.11 = 3.33 cm
Volume of future can (V2) = πr²h = 3.14*3.33²*13.32
= 3.14*11.0889*13.32 = 463.791025
V2 ≈ 463.79 cm³
==>Find how much more would new cans hold = Volume of new can - volume of current can
= 463.79 cm³ - 339.12 cm³
= 124.67cm³
Answer:
The answer to your question is 8 h
Step-by-step explanation:
Data
length of the ladder = 200 cm
distance between each rung = 20 cm
rate = 10 cm/h
fifth rung = ?
Process
1.- Calculate the total distance the tide must rise
distance = 20 cm x 4
= 80 cm because the first rung touches the water
2.- Calculate the time
rate = distance / time
-Solve for time
time = distance / rate
-Substitution
time = 80 cm / 10cm/h
-result
time = 8 h
Answer:
1000%
Step-by-step explanation:
c=10d,
3c will become 3*10d=30d
d is 10 times to c which converts to 1000%
<h2>-2+5i and 2+5i</h2>
Step-by-step explanation:
Let the complex numbers be
.
Given, sum is
, difference is
and product is
.
⇒ 
⇒ 


Hence, all three equations are consistent yielding the complex numbers
.