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ElenaW [278]
2 years ago
8

One hundred voters were asked their opinions of two candidates, a and b, running for mayor. their responses to three questions a

re summarized below number saying yes do you like a? 65 do you like b? 55 do you like both? 25 what is the probability that someone like exactly one given that they like at least one?
Mathematics
1 answer:
Harlamova29_29 [7]2 years ago
8 0

Answer:

I would be interested to hear from others here, but first if you draw a venn diagram with two circles, label them A and B for candidates A and B, the intersection will be 25(i.e. number of voters that like both candidates. that means A\B will be 40 (only voted for A) and B/A will be 30 (only voted for B).  Of course, 40 + 30 + 25 only equals 95, and there were 100 voters, which means 5 did not vote for either candidate.  So that 5 will be outside set A and B. The "At Least" question normally implies the probability axiom P(not E) = 1 - P(E).  

Step-by-step explanation:


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5. What is the area of the figure to the nearest square centimeter? It is composed of a symmetric hexagonand a semicircle 4 cm6
Nookie1986 [14]
=100.2743338823 which is 100
6 0
2 years ago
If 2A:3B=5:6 and 3B:2C=36:15 then find A:C​
Aleonysh [2.5K]

Answer:

A: C = 2: 1

Step-by-step explanation:

Please see the attached pictures for the full solution.

Further explanantion (2nd image):

The reason why the ratio of A: C is equal to the ratio if 2A: 2C is that the number of parts of A and C is equal, which is 2 parts. If I were to divide both 2A and 2C by 2 to find the ratio of A: C, I would obtain 15: 15/2. However, ratios are expressed as whole numbers and thus, we would multiply the whole ratio by 2 again and the answer would still be 30: 15. This ratio is not in the simplest form since both can be divided by 15. Thus, dividing both sides of the ratio by 15 will leave us with the final answer of

A: C= 2: 1.

☆ An alternative method is to simplify the ratio 3B: 2C at the beginning.

3B: 2C

= 36: 15

= 12: 5

Multiply the first ratio by 2 so 3B has 12 parts in both ratios:

2A: 3B

= 10: 12

Combining the 2 ratios together,

2A: 3B: 2C

= 10: 6: 5

2A: 2C

= 10: 5

= 2: 1

A: C= 2: 1

6 0
2 years ago
In a certain mid-size city, 90% of the high- school graduates are from public schools and the other 10% are from private schools
trapecia [35]
The answer should be .53
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Which term best describes the object shown in black in the rhombus below?
solong [7]
I think the answer is D.

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:)
4 0
2 years ago
Read 2 more answers
An investor believes that investing in domestic and international stocks will give a difference in the mean rate of return. They
arlik [135]

Answer:

So on this case the 90% confidence interval would be given by -4.137 \leq \mu_1 -\mu_2 \leq 2.087  

For this case since the confidence interval for the difference of means contains the 0 we can conclude that we don't have significant differences at 10% of significance between the two means analyzed.

Step-by-step explanation:

Previous concepts  

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

\bar X_1 =2.0233 represent the sample mean 1  

\bar X_2 =3.048 represent the sample mean 2  

n1=15 represent the sample 1 size  

n2=15 represent the sample 2 size  

s_1 =4.893387 population sample deviation for sample 1  

s_2 =5.12399 population sample deviation for sample 2  

\mu_1 -\mu_2 parameter of interest at 0.1 of significance so the confidence would be 0.9 or 90%

We want to test:

H0: \mu_1 = \mu_2

H1: \mu_1 \neq \mu_2

And we can do this using the confidence interval for the difference of means.

Solution to the problem  

The confidence interval for the difference of means is given by the following formula:  

(\bar X_1 -\bar X_2) \pm t_{\alpha/2}\sqrt{\frac{s^2_1}{n_1}+\frac{s^2_2}{n_2}} (1)  

The point of estimate for \mu_1 -\mu_2 is just given by:  

\bar X_1 -\bar X_2 =2.0233-3.048=-1.0247

The degrees of freedom are given by:

df = n_1 +n_2 -2 = 15+15-2=28  

Since the Confidence is 0.90 or 90%, the value of \alpha=0.1 and \alpha/2 =0.05, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.05,28)".And we see that t_{\alpha/2}=\pm 1.701  

Now we have everything in order to replace into formula (1):  

-1.0247-1.701\sqrt{\frac{4.893387^2}{15}+\frac{5.12399^2}{15}}=-4.137  

-1.0247+1.701\sqrt{\frac{4.893387^2}{15}+\frac{5.12399^2}{15}}=2.087  

So on this case the 90% confidence interval would be given by -4.137 \leq \mu_1 -\mu_2 \leq 2.087  

For this case since the confidence interval for the difference of means contains the 0 we can conclude that we don't have significant differences at 10% of significance between the two means analyzed.

4 0
2 years ago
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