We need to assign a value for x to check the possible values of y.
1st inequality: y < -0.75x
X = - 1 ; y < -0.75(-1) ; y < 0.75 possible coordinate (-1,0.75) LOCATED AT THE 2ND QUADRANT
X = 0 ; y < -0.75(0) ; y < 0 possible coordinate (0,0) ORIGIN
X = 1 ; y < -0.75(1) ; y < -0.75 possible coordinate (1,-0.75) LOCATED AT THE 4TH QUADRANT
2nd inequality: y < 3x -2
X = -1 ; y < 3(-1) – 2 ; y < -5 possible coordinate (-1,-5) LOCATED AT THE 4TH QUADRANT
X = 0 ; y < 3(0) – 2 ; y < -2 possible coordinate (0,-2) LOCATED AT THE 4TH QUADRANT
X = 1 ; y < 3(1) – 2 ; y <<span> 1 possible coordinate (1,1) LOCATED AT THE 1ST QUADRANT
The actual solution to the system lies on the 4TH QUADRANT.
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Answer:
The total cost function of having a party catered is f(p) = 65 + 9.50 p
Step-by-step explanation:
The equipment fee of the caterer = $65
The charge per plate = $9.50
Let, Total number of people invited in the party = p
So, the cost of plates of p people = Number of people x Per plate cost
= p x $9.50
Now, Total Catering Cost = Equipment Fee + Cost of all plates
or, Total cost = $65 + p x $9.50
Hence, the total cost function of having a party catered
is f(p) = 65 + 9.50 p.
Answer: "Use the straightedge to draw a line through points X and Y." is the right answer.
Step-by-step explanation:
To perpendicular bisector of line segment AB. There are following steps:
1) Draw arcs from points A and B on the both sides of AB.
2) Name the intersection points as X and Y.
3) Use the straightedge to draw a line through points X and Y.
4) Name the point as O
hence we have construct perpendicular bisector XY of AB which bisects at O.
Answer:
The predicted number of wins for a team that has an attendance of 2,100 is 25.49.
Step-by-step explanation:
The regression equation for the relationship between game attendance (in thousands) and the number of wins for baseball teams is as follows:

Here,
<em>y</em> = number of wins
<em>x</em> = attendance (in thousands)
Compute the number of wins for a team that has an attendance of 2,100 as follows:


Thus, the predicted number of wins for a team that has an attendance of 2,100 is 25.49.