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2 years ago

Which ordered pair is the best approximation of the exact solution?

Mathematics

2 answers:

tino4ka555 [31]2 years ago

4 0

For this case what you should do is observe the table that the values of y of both functions are as similar as possible.
We observed that:
For the x 1.6 coordinate we have:
$y = 1.2

y = 1.4$
Therefore, a good approximation of the solution is:
$\frac{(1.2 + 1.4)}{2} = 1.3 

$
The ordered pair solution is:
(1.6, 1.3)
Answer:
(1.6, 1.3)option A

sveticcg [70]2 years ago

3 0

Answer:

The correct option is A.

Step-by-step explanation:

The given table represent the value of two functions

$y=-3x+6$ .... (1)

$y=4x-5$ .... (2)

Equate both the equations to find the solution of the equations.

$-3x+6=4x-5$

Isolate like terms.

$6+5=4x+3x$

$11=7x$

$\frac{11}{7}=x$

$x\approx 1.571$

Put this value in equation (1).

$y=-3(1.571)+6$

$y\approx 1.287$

The solution of the system of equation is

$(1.571, 1.287)\approx (1.6,1.3)$

Therefore approximation of the exact solution is (1.6,1.3). The correct option is A.

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2 years ago

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2 years ago

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Phoenix [80]

Answer:

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Step-by-step explanation:

Given

$\frac{x}{4} - 2x^5 + \frac{x^3}{2} + 1$

Required

The standard form of the polynomial

The general form of a polynomial is

$ax^n + bx^{n-1} + cx^{n-2} +........+ k$

Where k is a constant and the terms are arranged from biggest to smallest exponents

We start by rearranging the given polynomial

$- 2x^5+ \frac{x^3}{2} +\frac{x}{4} + 1$

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$- 2x^5+ 0x^{n-1} + \frac{x^3}{2} +0x^{n-3}+\frac{x}{4} + 1$

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