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alina1380 [7]
2 years ago
15

Jared is placing chairs around of rectangular stage. The stage is 10 feet long and 22 feet wide. He wants to put a chair at each

corner and every 2 feet along the sides. How many chairs will Jared need for his stage?
Mathematics
2 answers:
Brut [27]2 years ago
6 0
The answer to the problem would be 20 chairs
marishachu [46]2 years ago
3 0
Hi there, I believe the answer is 20. Because, each corner is 4 chairs plus every two feet, equals 20. Hope this helps!
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If ray NP bisects <MNQ, m<MNQ=(8x+12)°, m<PNQ=78°, and m<RNM=(3y-9)°, find the value of x and y
aksik [14]

Step 1

<u>Find the measure of angle x</u>

we know that

If ray NP bisects <MNQ

then

m<MNQ=m<PNM+m<PNQ ------> equation A

and

m<PNM=m<PNQ -------> equation B

we have that

m<MNQ=(8x+12)°

m<PNQ=78°

so

substitute in equation A

(8x+12)=78+78-------> 8x+12=156------> 8x=156-12

8x=144------> x=18°

Step 2

<u>Find the measure of angle y</u>

we have

m<PNM=(3y-9)°

m<PNM=78°

so

3y-9=78------> 3y=87------> y=29°

therefore

<u>the answer is</u>

the measure of x is 18° and the measure of y is 29°


7 0
2 years ago
A force of 500.0 is represented graphically with its tail at the origin and the tip pointed in a direction 30.0° above the posit
trapecia [35]

Answer:

F^{'}=(250\sqrt{3},250 })

Step-by-step explanation:

We have F´ =500 and \alpha=30º, so x and y components:

F´ = (F_{x} , F_{y}) this is

F_{x} = F^{'} *Cos\alpha

F_{y} = F^{'} *Sin\alpha  

F_{x} = F`*Cos\alpha =500*Cos30=500*\frac{\sqrt{3} }{2} =250\sqrt{3}

F_{y}=F*Sin\alpha  =500*Sin30=500*\frac{1}{2}=250;

Finally

F' = (250\sqrt{3} , 250)

3 0
2 years ago
Which graph shows the solution to the system of linear inequalities? y &lt; 2x – 5 y &gt; –3x + 1
Ksenya-84 [330]

Answer:

Where are the graphs

Step-by-step explanation:


5 0
1 year ago
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Mr. Stephens uses 100 N of force to push the snake tank straight up 2 meters.
ArbitrLikvidat [17]
What is the question?
8 0
2 years ago
The sound intensity of rustling leaves is 100 times the reference intensity. Use your graph to determine the sound intensity of
wariber [46]

The sound intensity of rustling leaves,  y = 20 decibels

<u>Step-by-step explanation:</u>

y = 10logx

The sound intensity of rustling leaves is 100 times the reference intensity.

x = ratio of intensity of sound to reference to intensity

x = 100:1 or x = 100

y = 10 log(100) = 10 * 2 = 20 decibels

y = 20 decibels

4 0
1 year ago
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