Answer:
A. 57 mL/hr
Step-by-step explanation:
Mass of morphine sulfate = 125 mg
DW = 250 mL
Rate of infusion = 0.005 mg/kg/min
Converting to mg/kg/hour
0.005 mg/kg/min×60 = 0.3 mg/kg/hour
For the patient who weighs 95 kilograms
0.3 mg/kg/hour×95 = 28.5 mg/hour
For the mass of 125 mg of morphine sulfate
1 mg
250/150 = 2 ml/mg
Rate of infusion
28.5×2 = 57 mL/hr
∴ Rate of infusion is 57 mL/hr
Total weight = 50 lb
x = number of 3-lb weights
y = number of 10-lb weights
weight of 3-lb weights = 3x
weight of 10-lb weights = 10y
total weight = 3x + 10y
equation
3x + 10y = 50
Answer:
22.5 miles
Step-by-step explanation:
No traffic :
Let speed = x
Time taken = 30 = 30/60 = 0.5 hour
Speed = distance / time
Distance = d
x = d / 0.5 - - - (1)
With traffic :
Speed = x - 30
Time taken = 1 hour 30 minutes = 1.5 hour
x - 30 = d / 1.5
x = d/1.5 + 30 - - - - (2)
Equating (1) and (2)
d / 0.5 = d/1.5 + 30
d /0.5 - d /1.5 = 30
(1.5d - 0.5d) / 0.75 = 30
1.5d - 0.5d = 22.5
1d = 22.5
Hence,
d = 22.5 miles
Answer:
8
Step-by-step explanation:
The median is the segment from vertex B to the midpoint of AC. That midpoint (D) is ...
D = (A + C)/2 = ((-6, 7) +(-2, -9))/2 = (-8, -2)/2
D = (-4, -1)
The length of the midpoint is the length of the segment DB between (-4, -1) and (4, -1). These points both have the same y-coordinate, so the length is the difference of x-coordinates: 4 -(-4) = 8.
Answer:
a) Adding -5x on both sides of the equation to remove the smaller x-coefficient
b) Adding -4 on both sides will remove the constant from the right side of the equation
Step-by-step explanation:
Given equation:
5x + (−2) = 6x + 4
a) What tiles need to be added to both sides to remove the smaller x-coefficient?
Smaller x-coefficient is 5x to remove the smaller x-coefficient
So, Adding -5x on both sides of the equation to remove the smaller x-coefficient
b) What tiles need to be added to both sides to remove the constant from the right side of the equation?
the constant on right side is 4
Adding -4 on both sides will remove the constant from the right side of the equation
