See could have got the correct answer because if there was more numbers in the decimal you can round it to get .34 or because both answers have 12.3 and it doesnt matter about the other numbers after 3
The next step in his construction would have to be constructing the line between point M and point G. This is now your tangent line to the circle O. Additionally, you can also construct another tangent line that also passes through point M!
Answer:
The linear function that models the population of bloater fish is y2 =
✔ –92.57x + 1,052
.
The linear equation that determines when the two populations were equal is
✔ –19.76x + 227 = –92.57x + 1052
.
The solution is x =
✔ 11.33
years.
Step-by-step explanation:
Answer:
<em>A: For each increase in the number of procrastination days by 1, the predicted grade decreases by 3.64 points.</em>
Step-by-step explanation:
<u>The slope of a Regression Line</u>
A straight line can be represented in the slope-intercept form:
y = mx + b
Where m is the slope and b is the y-intercept.
The slope describes how fast and in what direction the graph goes when x changes values.
If m is positive, increments in x imply increments in y.
If m is negative, increments in x imply decrements in y.
The regression line is:
ŷ = –3.64x + 96.5
Where:
x = the number of procrastination days
ŷ = the predicted grade
We can say the slope is m=-3.64. This means that:
A: For each increase in the number of procrastination days by 1, the predicted grade decreases by 3.64 points.
To calculate this, the Hardy-Weinberg principle can be used:
p² + 2pq + q² = 1 and p + q = 1
where p and q are the frequencies of the alleles (p - dominant, q - recessive), and p², q² and 2pq are the frequencies of the genotypes.
a) Since 32 plants have rough seed (recessive genotype: q²) out of 100 plants in total, then
q² = 32/100 = 0.32
b) q = √q² = √0.32 = 0.56
c) Since p + q = 1, then
p = 1 - q = 1 - 0.56 = 0.44
d) 19 plants with rough seeds (recessive genotype: q²) in a population of 100 means that q² = 19/100 = 0.19
We need to calculate p (the allele frequency for smooth seeds).
We can find q because we know q²:
q = √q² = √0.19 = 0.44
Since p + q = 1, then
p = 1 - q = 1 - 0.4 = 0.56
