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Which data set is least Likely to resemble a normal distribution?<br> Look at picture

kicyunya [14]

Answer: B) The heights of girls who live on a certain street in the city of Buffalo

Every answer choice starts with "the heights of all 14-year-old girls who", so we can ignore that part. Choice A describes the largest population while choice B describes the smallest population. In other words, choice A is very general and broad, while choice B is very specific and narrow. The more specific you get and the smaller the population is, the less likely its going to be normally distributed.

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2 years ago

Which expression is the result of solving the equation ax - b = cy for 2? (For a + 0)

Masja [62]

I would say cy hopes this help

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2 years ago

Tonya plans to join a fitness club. She researched the costs to join different clubs in her area and found that there is a linea

Blababa [14]

Answer: The correct answer is 1

Step-by-step explanation:

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2 years ago

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Given the following two solids. Complete the following prompts using complete sentences. Write a hypothesis that compares the vo

Bess [88]

Now, there are many types of solids. Hypothesis can be stated as there is a significant discrepancy between solid one from the other sold. Moreover, if the results seems to support the hypothesis then it is somehow reliable and accurate.Thank you for your question. Please don't hesitate to ask in Brainly your queries.

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2 years ago

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52. In exploring possible sites for a convenience store in a large neighborhood, the retail chain wants to know the proportion o

kvasek [131]

Answer:

$n=\frac{0.5(1-0.5)}{(\frac{0.1}{1.96})^2}=96.04$

Then the minimum sample size in order to satisfy the condition of 0.1 for the margin of error is 97 and since the sample used is n =100 we can conclude that is sufficient and the best answer would be:

D. Yes.

Step-by-step explanation:

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. We know that we require a 95% of confidence, our significance level would be given by $\alpha=1-0.95=0.05$ and $\alpha/2 =0.025$ . And the critical value would be given by:

$z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96$

The margin of error for the proportion interval is given by this:

$ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$ (a)

We want a margin of error of $ME =\pm 0.1$ and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}$ (b)

Since we don't have prior info for the population proportion we can use as estimator the value of 0.5. And replacing into equation (b) the values from part a we got:

$n=\frac{0.5(1-0.5)}{(\frac{0.1}{1.96})^2}=96.04$

Then the minimum sample size in order to satisfy the condition of 0.1 for the margin of error is 97 and since the sample used is n =100 we can conclude that is sufficient and the best answer would be:

D. Yes.

4 0

2 years ago