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Oduvanchick [21]
2 years ago
10

Which expression is the result of solving the equation ax - b = cy for 2? (For a + 0)

Mathematics
1 answer:
Masja [62]2 years ago
6 0
I would say cy hopes this help
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The nth term of a sequence is 2n2 − 1 The nth term of a different sequence is 40 − n2 Show that there is only one number that is
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Answer:

Step-by-step explanation:

nth term of a sequence = 2n² - 1

Therefore, terms of the sequence will be,

1, 7, 17, 31, 49, ........... n terms

nth term of a different sequence = 40 - n²

Therefore, terms of the sequence will be,

39, 36, 31, 24, 15, 4, -9, -24 .......... n terms  

Since, there is no negative number in the first sequence,

Therefore, out of 6 positive terms of second sequence only one number (31) is common in both the sequences.

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Tad and Janice are installing new wood floors in a house. Tad can install 144 square feet of flooring in three hours. Janice can
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Answer:

1.) How many square feet of flooring can Tad install in eight hours? 384 square feet

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The two conditional relative frequency tables show the results of a neighborhood survey on the number and types of gardens in th
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A conical pile of road salt has a diameter of 112 feet and a slant height of 65 feet. After a storm, the linear dimensions of th
QveST [7]

we know that

the volume of a cone is equal to

V= \frac{1}{3} \pi r^{2}h

in this problem

the radius is equal to

r= \frac{112}{2}= 56ft

1) <u>Find the height of the cone before the storm</u>

Applying the Pythagorean Theorem find the height

h^{2} = l^{2}-r^{2}

l=65 ft

h^{2} = 65^{2}-56^{2}

h^{2} = 1,089

h=33 ft

2) <u>Find the volume before the storm</u>

V= \frac{1}{3}*\pi* 56^{2}*33

V=34,496\pi\ ft^{3}

3) <u>Find the volume after the storm</u>

After a storm, the linear dimensions of the pile are 1/3 of the original dimensions

so

r=(56/3) ft

h=(33/3)=11 ft

V= \frac{1}{3}*\pi* (56/3)^{2}*11

V= 1,277.63\pi\ ft^{3}

<u>4) Find how this change affect the volume of the pile</u>

Divide the volume after the storm by the volume before the storm

\frac{1,277.63 \pi }{34,496 \pi } = \frac{1}{27}

therefore

<u>the answer part a) is</u>

The volume of the pile after the storm is \frac{1}{27} times the original volume

<u>Part b)</u>  Estimate the number of lane miles that were covered with salt

5) <u>Find the amount of salt that was used during the storm</u>

=34,496 \pi - 1,277.63 \pi \\= 33.218.37 \pi \\= 104,358.59\ ft^{3}

6) <u>Find the pounds of road salt used</u>

104,358.59*80=8,348,687.2\ pounds    

7) <u>Find the number of lane miles that were covered with salt</u>

8,348,687.2/350=23,853.39 \ lane\ miles  

therefore

<u>the answer part b) is</u>

the number of lane miles that were covered with salt is 23,853.39 \ lane\ miles

<u>Part c) </u>How many lane miles can be covered with the remaining salt? Round your answer to the nearest lane mile

the remaining salt is equal to 1,277.63\pi\ ft^{3}

1,277.63\pi\ ft^{3}=4,013.79\ ft^{3}

8) <u>Find the pounds of road salt </u>

4,013.79*80=321,103.20\ pounds

9) <u>Find the number of lane miles </u>

321,103.20/350=917.44 \ lane\ miles

therefore

<u>the answer part c) is</u>

the number of lane miles is 917 \ lane\ miles

7 0
2 years ago
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