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guapka [62]
2 years ago
13

Given △DEF, which is not equal to cos(F)? sin(F). sin(D). tan(F). cos(D)

Mathematics
2 answers:
ivanzaharov [21]2 years ago
8 0

the answer is tan(F)

valentina_108 [34]2 years ago
3 0

Answer: The correct option is tan(F).

Explanation:

In the given figure the triangle is a right angle triangle because \angle E=90^{\circ}.

It is also given that DE=EF=5 and DF=5\sqrt{2}.

Since it is an isosceles right angle triangle, therefore the value of perpendicular and base is same for both angles D and F, which is 5.

\cos (F)=\frac{Base}{Hypotenuse} =\frac{5}{5\sqrt{2}} =\frac{1}{\sqrt{2}}

The value of cos(F) is \frac{1}{\sqrt{2}}.

\sin (F)=\frac{Perpendicular}{Hypotenuse} =\frac{5}{5\sqrt{2}} =\frac{1}{\sqrt{2}}

The value of sin(F) is \frac{1}{\sqrt{2}}.

\sin (D)=\frac{Perpendicular}{Hypotenuse} =\frac{5}{5\sqrt{2}} =\frac{1}{\sqrt{2}}

The value of sin(D) is \frac{1}{\sqrt{2}}.

\tan (F)=\frac{Perpendicular}{Base}=\frac{5}{5} =1

The value of tan(F) is 1. Which is not equal to \frac{1}{\sqrt{2}}.

\cos (D)=\frac{Base}{Hypotenuse} =\frac{5}{5\sqrt{2}} =\frac{1}{\sqrt{2}}

The value of cos(D) is \frac{1}{\sqrt{2}}.

Therefore, the value of tan(F) is not equal to the value of cos(F), so the correct option is third.

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