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LUCKY_DIMON [66]
2 years ago
12

The Great Lakes differ in both their areas (measured in square miles) and their depths. However these two dimensions do not keep

step perfectly. For example, Lake Michigan is exceeded in depth only by Lake Superior, but it is exceeded in area by both Lakes Superior and Huron. Lake Superior is by far the largest and deepest of the Great Lakes, but Lake Ontario, which is the smallest in area, is deeper than both Lakes Huron and Erie. Lake Erie is larger than Lake Ontario but it is not only shallower than Huron; it is also shallower than Ontario. Show the order of the Great Lakes according to depth.
Mathematics
1 answer:
Masteriza [31]2 years ago
3 0

Answer:

The order of Great Lakes according to depth is (descending order): 1. Lake Superior 2. Lake Michigan 3.  Lake Ontario 4. Lake Huron 5. Lake Erie

Step-by-step explanation:

Lake Superior is by far the largest and deepest of the great Lakes. Lake Michigan is exceeded in depth only by Lake Superior, but it is exceeded in area by both Lakes Superior and Huron. Lake Ontario, which is the smallest in area, is deeper than both Lakes Huron and Erie. Lake Erie is larger than Lake Ontario but it is not only shallower than Huron; it is also shallower than Ontario. So, the order of Great Lakes according to depth is (descending order): 1. Lake Superior 2. Lake Michigan 3.  Lake Ontario 4. Lake Huron 5. Lake Erie

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0.96%

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2 years ago
In triangle LTM, segment XY is the perpendicular bisector of side TM.
CaHeK987 [17]
The answer is c 100% i know this one lol
5 0
2 years ago
For a population with an unknown distribution, the form of the sampling distribution of the sample mean is _____.a. exactly norm
maxonik [38]

Answer:

Approximately normal for large sample sizes

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question:

The distribution is unknown, so the sampling distribution will only be approximately normal when n is at least 30.

So the correct answer should be:

Approximately normal for large sample sizes

7 0
2 years ago
Ice Cream Scoops - In shops with lots of ice-cream flavors there are many different flavor combinations, even with only a 2-scoo
blondinia [14]

Answer:

The general formula that can be used to find the required combinations for n flavor ice-cream.

N_n = \frac{n(n+1)}{2}

For 10 ice-cream flavors

N_{10} = \frac{10(10+1)}{2}

N_{10} = 55

Step-by-step explanation:

Let V = Vanila, C = Chocolate, S = Strawberry, P = Pineapple, B = Berry

2 ice-cream flavor:

V, C

{V/V, V/C, C/C}

3 possible combinations

3 ice-cream flavor:

V, C, S

{V/V, V/C, V/S, C/S, C/C, S/S}

6 possible combinations

4 ice-cream flavor:

V, C, S, P

{V/V, V/C, V/S, V/P, C/S, C/P, S/P, C/C, S/S, P/P}

10 possible combinations

5 ice-cream flavor:

V, C, S, P, B

{V/V, V/C, V/S, V/P, V/B, C/S, C/P, C/B, S/P, S/B, P/B, C/C, S/S, P/P, B/B }

15 possible combinations

So we have a series of

3, 6, 10, 15...

This series is known as Triangular number series

1 + 2 = 3

1 + 2 + 3 = 6

1 + 2 + 3 + 4 = 10

1 + 2 + 3 + 4 + 5 = 15

The general formula for this series is

N_n = \frac{n(n+1)}{2}

Using the above formula we can predict the number of 2-scoop combinations with 10 flavors.

N_{10} = \frac{10(10+1)}{2}

N_{10} = 55

Therefore, there are 55 different combinations of 2-scoop  with 10 flavors.

5 0
2 years ago
Annie is creating a stencil for her artwork using a coordinate plane. The beginning of the left edge of the stencil falls at (2,
taurus [48]

Answer:

(A)(12, 9)

Step-by-step explanation:

Given:

The beginning of the left edge of the stencil falls at (2, −1).

A point, say Q on the stencil is at  (4, 1).

Point Q divides the stencil into the ratio 1:4.

We are required to find the end of the stencil.

Mathematically, Point Q divides the stencil internally in the ratio 1:4.

For internal division of a line with beginning point (x_1,y_1) and end point (x_2,y_2) in the ratio m:n, we use the formula

Q(x,y)=(\dfrac{mx_2+nx_1}{m+n} ,\dfrac{my_2+ny_1}{m+n} )

(x_1,y_1)=(2, -1), (x_2,y_2)=?, Q(x,y)=(4,1), m:n=1:4

Therefore:

(4,1)=(\dfrac{1x_2+4*2}{1+4} ,\dfrac{1y_2+4*-1}{1+4} )\\(4,1)=(\dfrac{x_2+8}{5} ,\dfrac{y_2-4}{5} )\\$Therefore:\\\dfrac{x_2+8}{5}=4\\x_2+8=4X5\\x_2=20-8=12\\$Similarly\\\dfrac{y_2-4}{5}=1\\y_2-4=5\\y_2=4+5=9\\(x_2,y_2)=(12,9)

The correct option is A.

6 0
2 years ago
Read 2 more answers
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