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1 year ago

6

Tonya plans to join a fitness club. She researched the costs to join different clubs in her area and found that there is a linea

r relationship between the total cost of belonging to a club and the number of months that you are a member. Each club charges monthly dues, and some clubs require new members to also pay a one-time membership fee. The total costs of being a member for 6 months, 12 months, and 24 months at each of three clubs are shown in the table. Total Cost of Fitness Club Membership Length of membership Club 1 Club 2 Club 3 6 months $108 $120 $126 12 months $216 $210 $252 24 months $432 $390 $504 How many of the clubs require new members to pay a one-time membership fee? 0 1 2 3

2 answers:

tresset_1 [31]1 year ago

5 0

Answer:

1

Step-by-step explanation:

Blababa [14]1 year ago

4 0

Answer: The correct answer is 1

Step-by-step explanation:

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A painting crew reported that a job is 3/5 completed what is the fraction of the job remains to be done

HACTEHA [7]

Hi!

<h3>So we need to subtract 3/5 from a whole fraction. (5/5)</h3>

$\frac{5}{5}-\frac{3}{5}=-\frac{2}{5}$

<h2>The answer is 2/5</h2>

Hope this helps! :)

-Peredhel

5 0

2 years ago

Find the dimensions of the box with volume 1728 cm3 that has minimal surface area. (Let x, y, and z be the dimensions of the box

Gala2k [10]

Answer:

The dimensions of the box are 12 cm , 12 cm , 12 cm

Step-by-step explanation:

Let x , y and z be the dimensions of box

Volume of box =xyz=1728

$z=\frac{1728}{xy}$

Surface area of box = $2xy+2yz+2xz=2xy+2y(\frac{1728}{xy})+2x(\frac{1728}{xy})$

Let $f(x,y)=2xy+2(\frac{1728}{x})+2(\frac{1728}{y})$

To get minimal surface area

$\frac{\partial f}{\partial x}=0$ and $\frac{\partial f}{\partial y}=0$

$\frac{\partial(2xy+2(\frac{1728}{x})+2(\frac{1728}{y}))}{\partial x}=0$

$2y-2(\frac{1728}{x^2})=0$

$y=\frac{1728}{x^2}$ ----1

$\frac{\partial(2xy+2(\frac{1728}{x})+2(\frac{1728}{y}))}{\partial y}=0$

$2x-2(\frac{1728}{y^2})=0\\x=\frac{1728}{y^2} \\y^2=\frac{1728}{x}$

Using 1

$(\frac{1728}{x^2} )^2=\frac{1728}{x}$

x=0 and $x^3=1728$

Side can never be 0

So, $x^3=1728$

x=12

$y=\frac{1728}{x^2} \\y=\frac{1728}{12^2}$

y=12

$z=\frac{1728}{xy}\\z=\frac{1728}{(12)(12)}$

z=12

The dimensions of the box are 12 cm , 12 cm , 12 cm

5 0

2 years ago

What is the factored form of a2 – 121?

Flura [38]

Answer:

The factored form $a^2-121$ is $(a+11)(a-11)$ .

Step-by-step explanation:

Given : $a^2-121$

We have to write the given expression in factored form.

Factor form of an expression is writing the expression in lower power form such that the product of factors given the original expression

Consider the given expression $a^2-121$ .

We know the algebraic identity $x^2-y^2=(x+y)(x-y)$

Here $a^2-121=a^2-(11)^2$ .

Comparing with identity stated above , we have x= a , b = 11 , thus, we get

$a^2-(11)^2=(a+11)(a-11)$ .

Thus, the factored form $a^2-121$ is $(a+11)(a-11)$ .

7 0

2 years ago

6 people sharing 40 lbs of gold evenly. How many do they get? Then subtract 1 2/3 from the result of the problem above & sim

r-ruslan [8.4K]

Answer: 6

Step-by-step explanation:

Given Data:

Number of people = 6

Amount of Gold to be shared = 40lbs

Subtract 2/3 from your answer.

Therefore

If six people are to share 40lbs of gold evenly

= 40lbs / 6

Divide through by 2

= 20lbs / 3

= 20lbs / 3 - 2/3

= 18/3

= 6

Each person would get approximately 6lbs of gold

7 0

1 year ago

Read 2 more answers

What is the sum of StartRoot negative 2 EndRoot and StartRoot negative 18 EndRoot?

Crank

Answer:

<h2>B. 4 StartRoot 2 EndRoot i </h2>

Step-by-step explanation:

Given the surd function √-2 and √-18, we are to fund the sum of both values.

Taking the sum:

= √-2 + √-18

= (√2 * √-1)+ (√18 *√-1)

from complex numbers, √-1) = i

The expression becomes

= √2 i+ √18 i

= √2 i+ √9*2 i

= √2 i+ 3√2 i

= 4 √2 i

= √-2 + √-18 = 4 √2 i

The result is 4 StartRoot 2 EndRoot i

8 0

1 year ago

Read 2 more answers