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DiKsa [7]
1 year ago
7

Bianca and Meredith are sisters. Meredith's height is 23 of Bianca's height plus 32 inches. Meredith is 60 inches tall. A girl i

s sixty inches tall. Write an equation to find Bianca's height, x, in inches.
Mathematics
1 answer:
jarptica [38.1K]1 year ago
7 0

Answer:

Bianca's height = 42 inches

Step-by-step explanation:

Let x be the Bianca height.

Given:

Meredith height = 60 inches

We need to find the Bianca height.

Solution:

From the given statement the Meredith's height is \frac{2}{3} of Bianca's height plus 32 inches, so the equation is.

Meredith's height = \frac{2}{3}(Bianca\ height)+32

Substitute Meredith's height in above equation.

60=\frac{2}{3}x+32

Now we solve the above equation for x.

\frac{2}{3}x=60-32

\frac{2}{3}x=28

By cross multiplication.

x=\frac{3\times 28}{2}

28 divided by 2.

x= 3\times 14

x=42\ in

Therefore, the height of the Bianca is 42 inches.

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Answer:

D. We can be 95% confident that the proportion of all cell phone users who use text messaging is between 73.1% and 76.9%.

Step-by-step explanation:

The interpretation of a confidence interval of level x% means that we are x% sure that the interval contains the true mean of the population.

In this problem, we have that:

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The 95% confidence interval is (73.1%, 76.9%).

Which of the following is an appropriate interpretation of the 95% confidence interval?

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A triangle has two sides that are perpendicular. Could the triangle be isosceles, equilateral, or scalene? Explain.
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What is the product of (9) (negative 9) (negative 1)? –81 –1 1 81
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Answer:

Step-by-step explanation:

9 * -9 * -1 =

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(b) A department store has 7,000 charge accounts. The comptroller takes a random sample of 36 of
galben [10]

Answer:

a.0.8664

b. 0.23753

c. 0.15866

Step-by-step explanation:

The comptroller takes a random sample of 36 of the account balances and calculates the standard deviation to be N42.00. If the actual mean (1) of the account balances is N175.00, what is the probability that the sample mean would be between

a. N164.50 and N185.50?

b. greater than N180.00?

c. less than N168.00?

We solve the above question using z score formula

z = (x-μ)/σ/√n where

x is the raw score,

μ is the population mean = N175

σ is the population standard deviation = N42

n is random number of sample = 36

a. Between N164.50 and N185.50?

For x = N 164.50

z = 164.50 - 175/42 /√36

z = -1.5

Probability value from Z-Table:

P(x = 164.50) = 0.066807

For x = N185.50

z = 185.50 - 175/42 /√36

z =1.5

Probability value from Z-Table:

P(x=185.50) = 0.93319

Hence:

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= 0.93319 - 0.066807

= 0.866383

Approximately = 0.8664

b. greater than N180.00?

x > N 180

Hence:

z = 180 - 175/42 /√36

z = 5/42/6

z = 5/7

= 0.71429

Probability value from Z-Table:

P(x<180) = 0.76247

P(x>180) = 1 - P(x<180) = 0.23753

c. less than N168.00?

x < N168.

z = 168 - 175/42 /√36

z = -7/42/6

z = -7/7

z = -1

Probability value from Z-Table:

P(x<168) = 0.15866

4 0
1 year ago
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