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1 year ago

Explain why there are two sine ratios, two cosine ratios, and two tangent ratios for any right triangle

Mathematics

2 answers:

Elis [28]1 year ago

6 0

Answer with explanation:

There are two sine ratios, two cosine ratios, and two tangent ratios for any right triangle. It totally depends where the terminal side of right triangle lies. If it lies in first quadrant all trigonometric ratios will be positive .In second quadrant Sine and Cosecant of any angle will be positive.In Third tan and cot of any angle will be positive.And in fourth Quadrant secant and cos of any angle will be positive.So, there is one positive and one negative value of any of the trigonometric function.That's why all the trigonometric function have two real values.

taurus [48]1 year ago

5 0

Each angle has a sin, cos, and tan associated with it.
in a right angled triangle there are two other angles which each have ratios.

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The area of a trapezoid is 864 cm2. It has a height of 24 cm, and the length

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Answer:

Step-by-step explanation:

Area of trapezium = 1/2 × h (a+b) = 864 cm^2

where h is the height and a and b are the two parallel sides

h = 24 cm

a = 30 cm

b = ?

1/2 × 24 ( 30 + b ) = 864

12 ( 30 + b ) = 864

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2 years ago

The slope of the line below is -5/7 Write the point-slope equation of the line using the coordinates of the labeled point.

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Answer:

The answer is C) y - 2 = -5/7(x - 6)

Step-by-step explanation:

Since we have the slope (-5/7) and a point (6, 2), we can just input those in for m and (x1, y1) in point-slope form.

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Write the quadratic equation whose roots are six and -2 and who’s leading coefficient is 3 use the letter X to represent the var

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Answer:

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Step-by-step explanation:

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2 years ago

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Answer:

$\frac{\sqrt6 +\sqrt{11}}{\sqrt{5} + \sqrt{3}} \times \frac{\sqrt{5} - \sqrt{3}}{\sqrt{5} - \sqrt{3}} = \frac{\sqrt{30} - \sqrt{18} + \sqrt{55} - \sqrt{33}}{2}$

Step-by-step explanation:

Let's translate what you've written in words to an expression with mathematical symbols.

$\frac{\sqrt6 +\sqrt{11}}{\sqrt{5} + \sqrt{3}}$

To solve this, you need to multiply both the numerator and denominator with the conjugate of the denominator.

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