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2 years ago

Ifa team of three workers each making the us federal minimum wage 7.25 produce 12 rugs what would be total labor cost

Mathematics

1 answer:

Schach [20]2 years ago

3 0

Probably $87 based on the information I was given.

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Aseem and Stana are building model cars. Stana's car is 5 less than 2 times the length of Aseem's car. The sum of the lengths of

Ierofanga [76]

Answer:

1. 2x - 5 + x = 20

Step-by-step explanation:

Let Aseem's car as x,

Stana's = 5 less than 2x

= 2x - 5

Aseem's + Stana's = 20

x + 2x - 5 = 20

2x - 5 + x = 20

7 0

2 years ago

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Of the 1,500 muffins a bakery sold in one day, 1/3 were chocolate. how many chocolate muffins did the bakery sell?

lara [203]

That'd be one third of 1500 muffins, or 500 muffins.

3 0

2 years ago

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Given the graphed function below, which of the following ordered pairs are found on the inverse function?

Dmitrij [34]

Answer:

Its C (-9,-2)(-2,-1)(-1,0)(0,1)(7,2)

Step-by-step explanation:

4 0

2 years ago

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G find the area of the surface over the given region. use a computer algebra system to verify your results. the sphere r(u,v) =

Svetach [21]

Presumably you should be doing this using calculus methods, namely computing the surface integral along $\mathbf r(u,v)$ .

But since $\mathbf r(u,v)$ describes a sphere, we can simply recall that the surface area of a sphere of radius $a$ is $4\pi a^2$ .

In calculus terms, we would first find an expression for the surface element, which is given by

$\displaystyle\iint_S\mathrm dS=\iint_S\left\|\frac{\partial\mathbf r}{\partial u}\times\frac{\partial\mathbf r}{\partial v}\right\|\,\mathrm du\,\mathrm dv$

$\dfrac{\partial\mathbf r}{\partial u}=a\cos u\cos v\,\mathbf i+a\cos u\sin v\,\mathbf j-a\sin u\,\mathbf k$
$\dfrac{\partial\mathbf r}{\partial v}=-a\sin u\sin v\,\mathbf i+a\sin u\cos v\,\mathbf j$
$\implies\dfrac{\partial\mathbf r}{\partial u}\times\dfrac{\partial\mathbf r}{\partial v}=a^2\sin^2u\cos v\,\mathbf i+a^2\sin^2u\sin v\,\mathbf j+a^2\sin u\cos u\,\mathbf k$
$\implies\left\|\dfrac{\partial\mathbf r}{\partial u}\times\dfrac{\partial\mathbf r}{\partial v}\right\|=a^2\sin u$

So the area of the surface is

$\displaystyle\iint_S\mathrm dS=\int_{u=0}^{u=\pi}\int_{v=0}^{v=2\pi}a^2\sin u\,\mathrm dv\,\mathrm du=2\pi a^2\int_{u=0}^{u=\pi}\sin u$
$=-2\pi a^2(\cos\pi-\cos 0)$
$=-2\pi a^2(-1-1)$
$=4\pi a^2$

as expected.

6 0

2 years ago

A rectangle has an area of 256 cm 2 . it has a width that is 48 cm shorter than 4 times its length. what is the rectangle's leng

AveGali [126]

Let
x--------> the rectangle's length
y-------> the rectangle's width

we now that
Area of rectangle=x*y
Area=256 cm²
256=x*y-------> equation 1

y=4x-48------> y=4x-48------> equation 2

substitute equation 2 in equation 1

256=x*[4x-48]-----> 256=4x²-48x
4x²-48x-256=0

using a graph tool----> to resolve the second order equation
see the attached figure
the solution is
x=16 cm
y=4x-48----> y=4*16-48-----> y=16 cm

is a square

the answer is
the rectangle's length is 16 cm

8 0

2 years ago