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Juli2301 [7.4K]
2 years ago
12

A bank received an initial deposit of $12,000, kept a percentage of this money in reserve based on a reserve rate of 6%, and loa

ned out the rest. The amount it loaned out eventually was all deposited back into the bank. If this cycle continued indefinitely, how much money eventually resulted from the initial deposit?
A. $200,000
B. $72,000
C. $19,200
D. $20,000
Mathematics
1 answer:
blondinia [14]2 years ago
4 0
200,000 is the answer
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4. Lola is 15 years old and works in a factory every weekend. Why might this be illegal? What are the specific laws protecting L
gulaghasi [49]
This is not illegal because she is 15. in factories you have to be at least 15 years old. but age 16 is the appropriate age for you to work in a factory. 
5 0
2 years ago
4/9 of students at school are boys if there are 2601 students at the school how many are girls
hram777 [196]

Answer:

1445

Step-by-step explanation:

2601*(9/9-4/9)

4 0
2 years ago
Read 2 more answers
f(x) = −16x2 + 24x + 16 Part A: What are the x-intercepts of the graph of f(x)? Show your work. (2 points) Part B: Is the vertex
DerKrebs [107]

Answer:

see below

Step-by-step explanation:

f(x) = −16x^2 + 24x + 16

Set equal to zero to find the x intercepts

0  = −16x^2 + 24x + 16

Factor out -8

0 = -8(2x^2 -3x-2)

Factor

0 = -8(2x +1) (x-2)

Using the zero product property

2x+1 =0    x-2 =0

x = -1/2      x=2

The x intercepts are -1/2   ,2

Since the coefficient of x^2 is negative the graph will open down and the vertex will be a maximum

The x value of the maximum is 1/2 way between the zeros

(-1/2+2) /2 = 1.5/2 =.75

To find the y value substitute into the function

f(.75) = -8(2x +1) (x-2)

        =-8(2*.75+1) (.75-2)

        = -8(2.5)(-1.25)

         =25

The vertex is at (.75, 25)

We have the zeros, and  the vertex.  We know the graph is symmetrical about the vertex

3 0
2 years ago
I've been stuck on this for so long and I have an exam soon, anybody who can help me :'( ?
san4es73 [151]
(i)  speed = distance / time
so time =  distance / speed
here we have

time t = 1080/x  hours

(ii) return flight  time  = 1080 / (x + 30)  hours

(a)  1080/x - 1080/(x + 30) = 1/2

Multiplying  through by the LCD 2x(x + 30) we get:-

1080*2(x + 30) - 2x*1080 = x(x+30)
2160x + 64800 - 2160x = x^2 + 30x
x^2 + 30x - 64800  = 0

(b)  factoring;  -64800 = 270 * -240  ans 270-240 = 30 so we have

(x + 270)(x - 240) = 0   so x = 240  ( we ignore the negative -270)

So the speed for outward journey is 240 km/hr

(c) time ffor outward flight = 1080 / 240 =  4 1/2  hours

(d) average speed for whole flight = distance / time
   Time for outward journey = 4.5 hours and time for  return journey = d / v
= 1080 / (240+30) =  4 hours
 Therefore the average speed for whole journey =  2160 / 8.5 = 254.1 km/hr
8 0
2 years ago
Let ∠D be an acute angle such that cosD=0.33. Use a calculator to approximate the measure of ∠D to the nearest tenth of a degree
kotegsom [21]

To approximate the measure of angle D, we will need to use the inverse cosine function on our calculator. All calculators vary, so I am not sure where you would find the button for it on your calculator. However, I know many calculators have it so you click the second button, then cos.

cos(D) = 0.33

D = cos^-1 (0.33)

D = 70.7 degrees

Hope this helps!! :)

5 0
2 years ago
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