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Lena [83]
2 years ago
7

Enzo and Beatriz are playing games at their local arcade. Incredibly, Enzo wins 555 tickets from every game, and Beatriz wins 11

1111 tickets from every game. When they stopped playing games, Enzo and Beatriz had won the same number of total tickets. What is the minimum number of games that Enzo could have played?
Mathematics
2 answers:
Alexus [3.1K]2 years ago
7 0

Answer:

111111 number of games Enzo must play

Step-by-step explanation:

Enzo wins 555 tickets from every game, and Beatriz wins 111111 tickets from every game.

When they stopped playing games, Enzo and Beatriz had won the same number of total tickets. What is the minimum number of games that Enzo could have played?

To have the same number of tickets, Enzo and Beatriz each will have  555*111111=616666605 number of tickets.

For Enzo to have 616666605 (same number of tickets) tickets, he must play 111111 number of games.

Juli2301 [7.4K]2 years ago
6 0

Answer:

At least 55 games

Step-by-step explanation:

Given

Number of tickets won by

Enzo = 5

Beatriz = 11

Minimum number of games, played = ?

The minimum number of games played= the minimum number of tickets won.

Minimum number of tickets won is given by:

Enzo * Beatriz

= 5 * 11

= 55 tickets

So, the number of games played = the number of tickets won = At least 55 games

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Answer:

Step-by-step explanation:

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<u>Given:</u>

The given equation is \log _{4}(x)+\log _{4}(x-3)=\log _{4}(-7 x+21)

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To determine the extraneous solution, we shall first solve the given equation.

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Answer:

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