<span>To multiply two radicals together, we can simply multiply both the values inside the radicals together and put that in a radical.
So for 5*sqrt(45b) * 6*sqrt(48b), we get 30*sqrt(45b*48b) = 30*sqrt(2160b^2). This value can be simplified further by taking out b^2 and 12^2 from the radical giving us the answer 360b*sqrt(15).</span>
Answer:
5 ft
Step-by-step explanation:
Let the height of the previous jump be represented by j. Then 1.1j = 5.5 ft.
Dividing both sides by 1.1, we get j = 5 ft. This was the height of the previous jump.
The formula for slope is
Slope = Rise / Run = Risers / Treads
Slope = 7.75 in /10 in = 0.775
The slope Is 0.775.
The vertical distance is not continuous, thus it is
discrete. A discrete function only allows certain points in the interval. When
you walk up or down the stairs, the vertical distances are not continuous
because of the treads. You cannot stay also mid-air, so it should be discrete.
An example of a continuous function would be when you walk up or down an
inclined plane.
This is how the chart will look like:
Kermit Leonard Marlene Norma
Atley
Bradley
Cursen
Drake
1. Drake is Bradley's sister.
2. Cursen is Atley's brother
3. Norma and Drake are not related
<span>4. Kermit is a year older than Bradley
</span>
Drake is a girl (1), but she is not related to Norma(3), So she is Marlene.
1) MARLENE DRAKE
Drake and Bradley are related; Norma is not related to them(3). Norma can either be Atley or Cursen. But, Cursen is Male. So, Norma is NORMA ATLEY
Remaining family names are Bradley and Cursen. Kermit is not a Bradley, so he is KERMIT CURSEN. That leaves LEONARD BRADLEY.
Answer:
The probability that a defective rod can be salvaged = 0.50
Step-by-step explanation:
Given that:
A machine shop produces heavy duty high endurance 20-inch rods
On occasion, the machine malfunctions and produces a groove or a chisel cut mark somewhere on the rod.
If such defective rods can be cut so that there is at least 15 consecutive inches without a groove.
Then; The defective rod can be salvaged if the groove lies on the rod between 0 and 5 inches i.e ( 20 - 15 )inches
Now:
P(X ≤ 5) = 
= 0.25
P(X ≥ 15) =
= 0.25
The probability that a defective rod can be salvaged = P(X ≤ 5) + P(X ≥ 15)
= 0.25+0.25
= 0.50
∴ The probability that a defective rod can be salvaged = 0.50
