Answer:
B. first step
6/7x=7/8-1/2
c. second step
6/7x=7/8-4/8=3/8
d. and e are the same
x=3/8x7/6
Step-by-step explanation:
9514 1404 393
Answer:
40·713 and 8·713
Step-by-step explanation:
When this multiplication is carried out "by hand", the usual sum of partial products is ...
8·713 + 40·713
Answer:
Step-by-step explanation:
For the random variable 
we define the possible values for this variable on this case ![[1,2,3,4,5]](https://tex.z-dn.net/?f=%20%5B1%2C2%2C3%2C4%2C5%5D)
. We know that we have 2 defective transistors so then we have 5C2 (where C means combinatory) ways to select or permute the transistors in order to detect the first defective:
We want the first detective transistor on the ath place, so then the first a-1 places are non defective transistors, so then we can define the probability for the random variable 
like this:
For the distribution of 
we need to take in count that we are finding a conditional distribution. given 
, for this case we see that ![N_2 \in [1,2,...,5-a]](https://tex.z-dn.net/?f=%20N_2%20%5Cin%20%5B1%2C2%2C...%2C5-a%5D)
, so then exist 
ways to reorder the remaining transistors. And if we want b additional steps to obtain a second defective transistor we have the following probability defined:
And if we want to find the joint probability we just need to do this:
And if we multiply the probabilities founded we got:
Answer:
4
Step-by-step explanation:
the answer is 4 so d on edge .
