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podryga [215]
2 years ago
7

Leonora is factoring a trinomial. The factors of the trinomial are shown on the model. An algebra tile configuration. 7 tiles ar

e in the Factor 1 spot: 1 is labeled + x and 6 are labeled negative. 3 tiles are in the Factor 2 spot: 1 is labeled + x and 2 are labeled +. 0 tiles are in the Product spot. Which trinomial did she factor? x2 + 4x – 12 x2 + 2x – 6 x2 – 8x – 6 x2 – 4x – 12
Mathematics
1 answer:
Keith_Richards [23]2 years ago
6 0
Leanora is factoring in Amacher the factors of the thermometer are shown in the elevator 3+3 = 7 4+4 equalsTake away 100 and then +3 that gives you 6 billion in 2/3+6+4+3+8+9 that gives you a BCDEFGHIJK jelly jelly jelly diaper
You might be interested in
What proportion results in the equation 9m=10n
Serhud [2]
Give the equation 9m = 10n

Dividing both sides by 9n, we have
\frac{9m}{9n} = \frac{10n}{9n}  \\  \\  \frac{m}{n} = \frac{10}{9}

Therefore, the <span>proportion that results in the equation 9m = 10n is
\frac{m}{n}=\frac{10}{9}
</span>
4 0
2 years ago
Read 2 more answers
If mJK=(7x-39) and mML)=87, find x
lilavasa [31]
If two chords of a circle are congruent, then their intercepted arcs are congruent
7x-39 = 87
7x = 87 + 39
7x = 126
x = 126/7
x = 18
5 0
2 years ago
The cost of producing 4 metal units is 204.80. The cost of producing 8 units is 209.60. What is the cost to produce 12
inessss [21]
The cost of 12 units would be $614.40.

This is found by dividing $204.80 by 4 to get $51.20 (cost per single unit), then multiplying $51.20 by 12 to get $614.40 (cost for 12 units).

I hope this helps!
3 0
2 years ago
Read 2 more answers
In each figure, a|| b . Determine whether the third figure is a translation image of the first figure. Write yes or no. Explain
stellarik [79]

Answer should be:

b. No; it is a reflection followed by a translation.

Hope it helps.

4 0
2 years ago
Read 2 more answers
44. Express each of these system specifications using predicates, quantifiers, and logical connectives. a) Every user has access
DENIUS [597]

Answer:

a. ∀x (User(x) → (∃y (Mailbox(y) ∧ Access(x, y))))

b. FileSystemLocked → ∀x Access(x, SystemMailbox)

c. ∀x ∀y ((Firewall(x) ∧ Diagnostic(x)) → (ProxyServer(y) → Diagnostic(y))

d. ∀x (ThroughputNormal ∧(ProxyServer(x)∧ ¬Diagnostic(x))) → (∃y Router(y)∧Functioning(y))

Step-by-step explanation:

a)  

Let the domain be users and mailboxes. Let User(x) be “x is a user”, let Mailbox(y) be “y is a mailbox”, and let Access(x, y) be “x has access to y”.  

∀x (User(x) → (∃y (Mailbox(y) ∧ Access(x, y))))  

(b)

Let the domain be people in the group. Let Access(x, y) be “x has access to y”. Let FileSystemLocked be the proposition “the file system is locked.” Let System Mailbox be the constant that is the system mailbox.  

FileSystemLocked → ∀x Access(x, SystemMailbox)  

(c)  

Let the domain be all applications. Let Firewall(x) be “x is the firewall”, and let ProxyServer(x) be “x is the proxy server.” Let Diagnostic(x) be “x is in a diagnostic state”.  

∀x ∀y ((Firewall(x) ∧ Diagnostic(x)) → (ProxyServer(y) → Diagnostic(y))  

(d)

Let the domain be all applications and routers. Let Router(x) be “x is a router”, and let ProxyServer(x) be “x is the proxy server.” Let Diagnostic(x) be “x is in a diagnostic state”. Let ThroughputNormal be “the throughput is between 100kbps and 500 kbps”. Let Functioning(y) be “y is functioning normally”.  

∀x (ThroughputNormal ∧(ProxyServer(x)∧ ¬Diagnostic(x))) → (∃y Router(y)∧Functioning(y))

4 0
2 years ago
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