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morpeh [17]
2 years ago
13

A portfolio has average return of 13.2 percent and standard deviation of returns of 18.9 percent. Assuming that the portfolioi's

returns are normally distributed, what is the probability that the portfolio's return in any given year is between -43.5 percent and 32.1 percent?
A. 0.950
B. 0.835
C. 0.815
D. 0.970
Mathematics
1 answer:
wlad13 [49]2 years ago
6 0

Answer:

B. 0.835

Step-by-step explanation:

We can use the z-scores and the standard normal distribution to calculate this probability.

We have a normal distribution for the portfolio return, with mean 13.2 and standard deviation 18.9.

We have to calculate the probability that the portfolio's return in any given year is between -43.5 and 32.1.

Then, the z-scores for X=-43.5 and 32.1 are:

z_1=\dfrac{X_1-\mu}{\sigma}=\dfrac{(-43.5)-13.2}{18.9}=\dfrac{-56.7}{18.9}=-3\\\\\\z_2=\dfrac{X_2-\mu}{\sigma}=\dfrac{32.1-13.2}{18.9}=\dfrac{18.9}{18.9}=1\\\\\\

Then, the probability that the portfolio's return in any given year is between -43.5 and 32.1 is:

P(-43.5

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Inessa05 [86]
<h3><u>Question:</u></h3>

Denzel earned money after school. He put 1/2 of this month's earnings into savings. He took the rest to spend at the amusement park. He spent 1/5 of this amount on popcorn and 3/4 of it on rides. What fraction of his earnings did he take to the park but not spend on rides or popcorn.

<h3><u>Answer:</u></h3>

\frac{1}{40} fraction of money not spend in amusement park

<h3><u>Solution:</u></h3>

Let "x" be the total earnings

He put 1/2 of this month's earnings into savings

\text{ savings} = \frac{1}{2} \text{ of } x

\text{ savings} = \frac{1}{2}x = \frac{x}{2}

He took the rest to spend at the amusement park

\text{ Remaining amount }= x - \frac{x}{2}\\\\\text{ Remaining amount } = \frac{2x - x}{2} = \frac{x}{2}

He spent 1/5 of this amount on popcorn and 3/4 of it on rides

\text{ Amount spend on popcorn } = \frac{1}{5} \times \frac{x}{2} = \frac{x}{10}

\text{ amount spend on rides } = \frac{3}{4} \times \frac{x}{2} = \frac{3x}{8}

<em><u>So the fraction of money not spend in amusement park is:</u></em>

⇒ Remaining amount - (Amount spend on popcorn + amount spend on rides)

\rightarrow \frac{x}{2} - (\frac{x}{10} + \frac{3x}{8})\\\\\rightarrow \frac{x}{2} - \frac{38x}{80}\\\\\rightarrow \frac{2x}{80} = \frac{x}{40}

Thus \frac{1}{40} fraction of money not spend in amusement park

8 0
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2 years ago
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m is the middle ordinate 
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Next, to find the minimum speed, we are going to use the formula: s= \sqrt{15fr}
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f is <span>drag factor
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a manufacturer of cat toys produces three different toys filled with catnip the toys are the shape of a cone cylinder sphere eac
OLEGan [10]

Statements A, B, and C are true.

Step-by-step explanation:

Step 1:

A cone, a cylinder and a sphere all have radii of 3 inches. The cone and cylinder have heights of 2 inches.

The volume of the cone, V=\pi r^{2} \frac{h}{3}. Here r = 3 inches and h = 2 inches.

So the volume of the cone  =\pi r^{2} \frac{h}{3} = \pi (3^{2}) \frac{2}{3} = 18.85 cubic inches.

The volume of the cylinder, V=\pi r^{2} h. Here r = 3 inches and h = 2 inches.

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The volume of the sphere, V=\frac{4}{3} \pi r^{3}. Here r = 3 inches.

So the volume of the sphere =\frac{4}{3} \pi (3^{3})= 113.1 cubic inches.

Step 2:

Now we check to see which statements are true.

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B. About 18.8 cubic inches of catnip will fit inside a cone-shaped toy so it true.

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P.S. I couldn't see the options B, D, and E completely.

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