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ki77a [65]
2 years ago
15

Figure ABCD is transformed to obtain figure A'B'C'D': A coordinate grid is shown from negative 6 to 6 on both axes at increments

of 1. Figure ABCD has A at ordered pair negative 4, 4, B at negative 2, 2, C at negative 2, negative 1, D at negative 4, 1. Figure A prime B prime C prime D prime has A prime at ordered pair 3, negative 4, B prime at 5, negative 2, C prime at 5, 1, D prime at 3, negative 1. Part A: Write the sequence of transformations that changes figure ABCD to figure A'B'C'D'. Explain your answer and write the coordinates of the figure obtained after each transformation. (6 points) Part B: Are the two figures congruent? Explain your answer. (4 points)

Mathematics
1 answer:
nika2105 [10]2 years ago
8 0

Given:

Vertices of ABCD are A(-4,4), (-2,2), C(-2,-1) and D(-4,1).

Vertices of A'B'C'D' are A'(3,-4), B'(5,-2), C'(5,1) and D'(3,-1).

To find:

The sequence of transformations that changes figure ABCD to figure A'B'C'D'.

Solution:

Part A:

The figure ABCD reflected across the x-axis, then

(x,y)\to (x,-y)

Using this rule, we get

A(-4,4)\to A_1(-4,-4)

Similarly, the other points are B_1(-2,-2),C_1(-2,1),D_1(-4,-1).

Then figure translated 7 units right to get A'B'C'D'.

(x,y)\to (x+7,y)

A_1(-4,-4)\to A'(-4+7,-4)=A'(3,-4)

Similarly, the other points are B'(5,-2), C'(5,1),D'(3,-1).

Therefore, the figure ABCD reflected across the x-axis and then translated 7 units right to get A'B'C'D'.

Part B:

Reflection and translation are rigid transformation, it means shape and size of figures remains same after reflection and translation.

Therefore, the two figures congruent.

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Answer:

<u>Option B</u>

Step-by-step explanation:

The question is as following:

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Step Work Justification

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Which of the following has all of the correct justifications Wyatt used to solve this equation?

A. Distributive property. 2. Combine like terms. 3. Addition property of equality. 4. Division property of equality.

B. Multiplication property of equality. 2. Combine like terms. 3. Addition property of equality. 4. Division property of equality.

C. Distributive property. 2. Combine like terms. 3. Subtraction property of equality. 4. Division property of equality.

D. Multiplication property of equality. 2. Combine like terms. 3. Subtraction property of equality. 4. Division property of equality

<u />

<u>The answer:</u>

Step Work Justification

multiply both sides by 2

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{Combine like terms}

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The answer is option B

(B) Multiplication property of equality. 2. Combine like terms. 3. Addition property of equality. 4. Division property of equality.

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as far as I can tell, is just a matter of going around the circle many or infinite times around.

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