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kotykmax [81]
2 years ago
10

A certain spring has a resting length of 0.08 m (8 cm) when it is not stretched. The spring is stretched to a length of 0.10 m (

10 cm), 0.02 m beyond its natural length. Holding it in this stretched position requires a force of 20 N. Question: What is the force function for this spring? Answer: Hooke's Law says that the force required to maintain the spring in a stretched position is the linear function F(x) = kx. Find the spring constant, k, for the spring described above, and enter that number as your final answer.
Mathematics
1 answer:
slavikrds [6]2 years ago
8 0

Answer:

The spring constant is   k  =1000 \ N/m

Step-by-step explanation:

From the question we are told that

     The resting length is x =  0.08 \ m

        The extension of spring is  e =  0.02 \ m

      The new length of spring is  l =  0.10 \ m

       The force is  F =  20 \ N

The spring constant is

         k  = \frac{F}{e}

substituting values

         k  = \frac{20}{0.02}

        k  =1000 \ N/m

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