Question

A spinner has three equal sections labeled 1, 2, and 3. It is spun twice. Which expression can be used to determine P(2, then 1)?

Answer 1

1/3 . 1/3 i just took the test.

Answer 2

Answer:

$\frac{1}{9}$

Step-by-step explanation:

Given :A spinner has three equal sections labeled 1, 2, and 3. It is spun twice.

Solution :Which expression can be used to determine P(2, then 1)?

Solution :

Total no. of events = {1,2,3}=3

When it is spin for the first time .

Since we are given in the first spin she should get 2

No. of Favorable events ={2}=1

probability of getting 2 = $\frac{\text{No. of favorable events}}{\text{No. of total events}}$

= 1/3

In second spin she should get 1

No. of Favorable events ={1}=1

probability of getting 1= $\frac{\text{No. of favorable events}}{\text{No. of total events}}$

=$\frac{1}{3}$

Thus  P(2, then 1) = $\frac{1}{3} *\frac{1}{3}$

Hence the expression : P(2, then 1) = $\frac{1}{3} *\frac{1}{3}$

                                                         = $\frac{1}{9}$