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2 years ago

Is a x a +15a + 75 a perfect square trinomial

1 answer:

5 0

Factoring. A trinomial is a perfect square trinomial if it can be factored into a binomial multiplied to itself. (This is the part where you are moving the other way). In a perfect square trinomial, two of your terms will be perfect squares.

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-6/5 divided by 12/25

Tema [17]

Answer:

-1 17/25

Solution with Steps

−65−1225=?

The fractions have unlike denominators. First, find the Least Common Denominator and rewrite the fractions with the common denominator.

LCD(-6/5, 12/25) = 25

Multiply both the numerator and denominator of each fraction by the number that makes its denominator equal the LCD. This is basically multiplying each fraction by 1.

(−65×55)−(1225×11)=?

Complete the multiplication and the equation becomes

−3025−1225=?

The two fractions now have like denominators so you can subtract the numerators.

Then:

−30−1225=−4225

This fraction cannot be reduced.

The fraction

−4225

is the same as

−42÷25

Convert to a mixed number using

long division for -42 ÷ 25 = -1R17, so

−4225=−11725

Therefore:

−65−1225=−11725

4 0

2 years ago

An employee receives a pay increase from $35,000 per year to $37,500 per year. Calculate the percent increase. Round to the near

arsen [322]

Answer:

The percentage increase in salary of employee is 7.14 %

Step-by-step explanation:

Given as :

The initial pay of employee = $35,000 per year

The increase pay of employee = $37,500 per year

Let The percentage increase in salary = X %

So, X = $\frac{increase salary - initial salary}{initial salary}$ × 100

Or, X = $\frac{$37,500 - $35,000}{$35,000}$ × 100

Or, X = $\frac{$2,500}{$35,000}$ × 100

∴ X = 0.0714 × 100 = 7.14 %

Hence The percentage increase in salary of employee is 7.14 % Answer

8 0

2 years ago

Read 2 more answers

Paul joins a gym that has an initial membership fee and a monthly cost. He pays a total of $295 after three months, and $495 aft

Harrizon [31]

Answer:

Step-by-step explanation:

6 0

1 year ago

For the members of a book group, the probability of randomly selecting a member who likes to read historical fiction is 47%, the

umka2103 [35]

Answer:

75%

Step-by-step explanation:

8 0

1 year ago

Player V and Player M have competed against each other many times. Historical data show that each player is equally likely to wi

Helen [10]

Answer:

0.46 (46%)

Step-by-step explanation:

We have the following data:

- Probability that player V wins the first set:

$p(1)=0.50$

(because the text says the two players are equally likely to win the first set)

- Probability that player V wins the 2nd set if he has won the 1st set:

$p(2|1)=0.60$

So, the probability that player V wins the first 2 sets is:

$p(12)=p(1)\cdot p(2|1)=(0.50)(0.60)=0.30$ (1)

Instead, the probability that player V loses the 2nd set if he has won the 1st set is 0.40 (=1-0.60), so

$p(2^c|1)=0.40$

So, the probabiity that player V winse the 1st set but loses the 2nd set is

$p(12^c)=p(1)\cdot p(2^c|1)=(0.50)(0.40)=0.20$ (2)

Also, we have:

- Probability that player V loses the 1st set:

$p(1^c)=0.50$

- Probability that she will lose the 2nd set in this case is 0.70, it means that the probability that she will win the 2nd set if she lost the 1st set is 0.30, so:

$p(2|1^c)=0.30$