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2 years ago

(I may give brainliest) The roof of a lean-to-garden shed has a gradient of 0.35.find the height?

Mathematics

2 answers:

Sonbull [250]2 years ago

8 0

Answer:

the answer is 2.7

Step-by-step explanation:

UkoKoshka [18]2 years ago

3 0

Answer: 2.325 meters

Step-by-step explanation:

The roof of a lean-to-garden shed has a gradient of 0.35.find the height....they have given the base as 1.5m and a shorter height 1.8m its like a house

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It sounds like you have a right triangle with base = 1.5,

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Use a proportion to get:

(height of that triangle)/1.5 = 35/100

height of that triangle = 1.5*0.35 = 0.5250

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greater height of the lean-to = 1.8 + 0.5250 = 2.325 meters

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Circle L is shown. Line segments K L and M L are radii. The length of K L is 12. Angle M L K is 60 degrees. Sector M L K with a

sergejj [24]

Answer:

$120\pi$ square units

Step-by-step explanation:

We are given that

Radius of circle=12 units

Angle MLK=60 degree

We have to find the area of sector that is not shaded.

Area of shaded sector MLK= $\frac{\theta}{360}\times \pi r^2$

Area of shaded sector MLK= $\frac{60}{360}\times \pi(12)^2=$ 24 square units

Area of whole circle= $\pi r^2=\pi (12)^2=144\pi$ square units

Area of sector that is not shaded =Area of whole circle-Area of shaded sector MLK= $144\pi-24\pi$

Area of sector that is not shaded= $120\pi$ square units

4 0

2 years ago

Read 2 more answers

Candidate A is facing two opposing candidates in a mayoral election. In a recent poll of 300 residents, 98 supported candidate B

babymother [125]

Answer:

[0.4235, 0.5365]

Step-by-step explanation:

Data given and notation

n=300 represent the random sample taken

X=300-98-58=144 represent the people that support the candidate A in the sample

$\hat p=\frac{144}{300}=0.48$ estimated proportion of people that support the candidate A in the sample

$\alpha=0.05$ represent the significance level

Confidence =0.95 or 95%

p= population proportion of people that support the candidate A.

Confidence interval

The confidence interval would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 95% confidence interval the value of $\alpha=1-0.95=0.05$ and $\alpha/2=0.025$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=1.96$

And replacing into the confidence interval formula we got:

$0.48 - 1.96 \sqrt{\frac{0.48(1-0.48)}{300}}=0.4235$

$0.48 + 1.96 \sqrt{\frac{0.48(1-0.48)}{300}}=0.5365$

And the 95% confidence interval would be given (0.4235;0.5365).

$0.4235 \leq p \leq 0.5365$

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2 years ago

Which equation describes this line?

Anettt [7]

The last equation would best describe the line.

y-4=3(x+2)

y-4=3x + 6

y=3x + 10

4 0

2 years ago

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At the rate of $2.00 per square foot the cost of painting the rectangular board with a semicircular top shown in the figure is $

Elenna [48]

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions here.
<span>
it consists of a rectangle, dimensions L = 4ft and W = 3ft = Ar = 4ft x 3ft = 12 ft^2

</span>then, you have one half of the area of the circle that has diameter R = 3ft - radius will be r = 1.5ft the area of that half will be:

Ac = r^2 $\pi$ / 2
= (1.5 ft)^2 x 3.14 / 2
= 2.25 ft^2 x 3.4/2
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A = Ar + Ac
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A = 15.5325ft^2

<span>At the rate of $2 per square foot, the cost will be:
$ 15.5325*2 = 31.07 </span>

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2 years ago

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telo118 [61]

With the choices you gave, the answer to this question is the first statement, "2 loaves of bread and 4 batches of muffins''. I arrived with the answer through multiplying the amount of flour and sugar required for each loaf of bread and batch of muffins.

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2 years ago