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klasskru [66]
2 years ago
10

Lauren is shopping and finds 6 bracelets, 2 pairs of earrings, and 3 necklaces that she likes. How many ways can Lauren select 4

pieces of jewelry to buy?
Mathematics
2 answers:
Grace [21]2 years ago
5 0
Because it does not specify that she has to choose one or two from each category all pieces of jewelry can be treated as choices in a combination set.

the formula for a combination is

C(n,r)= \frac{n!}{r!(n-r)!}

where n is a total number of choices ( 11 ) 
and r is number chosen out of those choices (4)
 so

C(11,4)= \frac{11!}{4!(11-4)!} 

She has 330 possible choices  to come home with 4 pieces of jewelry



Rama09 [41]2 years ago
3 0

Answer:

the correct answer is b)

Step-by-step explanation:

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<h2>p(B) = 8310</h2>

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