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klasskru [66]
2 years ago
10

Lauren is shopping and finds 6 bracelets, 2 pairs of earrings, and 3 necklaces that she likes. How many ways can Lauren select 4

pieces of jewelry to buy?
Mathematics
2 answers:
Grace [21]2 years ago
5 0
Because it does not specify that she has to choose one or two from each category all pieces of jewelry can be treated as choices in a combination set.

the formula for a combination is

C(n,r)= \frac{n!}{r!(n-r)!}

where n is a total number of choices ( 11 ) 
and r is number chosen out of those choices (4)
 so

C(11,4)= \frac{11!}{4!(11-4)!} 

She has 330 possible choices  to come home with 4 pieces of jewelry



Rama09 [41]2 years ago
3 0

Answer:

the correct answer is b)

Step-by-step explanation:

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tia_tia [17]

Answer:

Natalia's work is wrong.

Step-by-step explanation:

Natalia divided a decimal number by an entire number. Since division is a operation derived from multiplication, the best approach to check if work was good is multiplying the given result by denomination, that is:

1) x = 6.2\times 12 Given.

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5 0
1 year ago
Libby sold $60 worth of vegetables at the farmer's market. Jess sold 3/4ths of what Libby sold. Stephanie sold 1/3rd of what Jes
Gemiola [76]

Answer:

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Step-by-step explanation:

We have been given that Libby sold $60 worth of vegetables at the farmer's market.

Jess sold 3/4th of what Libby sold. Let us find 3/4 of 60.

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\text{Jess sold}=15\times 3

\text{Jess sold}=45

Therefore, Jess sold $45 worth of vegetables.

We are told that Stephanie sold 1/3rd of what Jess sold. So let us 1/3rd of 45.

\text{Stephanie sold}=45\times \frac{1}{3}

\text{Stephanie sold}=15

Therefore Stephanie sold $15 worth of vegetables.

Now let us add amounts of money earned by Libby, Jess and Stephanie to get the total money earned by all.

\text{The total money earned by Libby, Jess and Stephanie}=60+45+15

\text{The total money earned by Libby, Jess and Stephanie}=120

Therefore, they all sell $120 worth of vegetables together.

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