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galben [10]
2 years ago
9

Triangle ABC is translated according to the rule (x, y) → (x + 2, y – 8). If the coordinates of the pre-image of point B are (4,

–5), what are the coordinates of B'?
Mathematics
2 answers:
Fed [463]2 years ago
8 0
*Hint: In order to find the coordinates, you plug in the coordinates into the rule and solve.

(x, y) → (x + 2, y - 8)
(4, -5) → (4 + 2, -5 - 8)
(6, -13)

The coordinates of B' is (6, -13).
vredina [299]2 years ago
7 0

Answer:  The co-ordinates of point B' are (6, -13).

Step-by-step explanation:  Given that triangle ABC is translated according to the following rule:

(x,y)~~~\rightarrow~~~(x+2,y-5).

We are to find the co-ordinates of B' if the co-ordinates of the pre-image of point B are (4, -5).

Since the co-ordinates of point B are (4, -5), so the co-ordinates of point B' will be

(4,-5)~~~\rightarrow~~~(4+2,-5-8)=(6,-13).

Thus, the co-ordinates of point B' are (6, -13).

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butalik [34]
The statment is correct but if you have to work out the value of x you need a total amount of the purchase without that or atleast some sort of value it is not possible to work out
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2 years ago
Can anyone please help me with this question? : A target consists of two concentric circles. The larger circle has diameter 1m.
11111nata11111 [884]
We know that
if  <span>the probability of hitting the blue circle is the same as the probability of hitting the green region
then 
the area of the blue circle is equal to the area of the green region

Let
x----> diameter of the blue circle

area of the blue circle=pi*(x/2)</span>²----> (pi/4)*x² m²-----> equation 1

area of the green region=area of the larger circle-area of the blue circle
area of the green region=pi*(1/2)²-(pi/4)*x²
=(pi/4)-(pi/4)*x² m²----> equation 2

equate equation 1 and equation 2
(pi/4)*x²=(pi/4)-(pi/4)*x² -----> divide by (pi/4)---> x²=1-x²
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5 0
2 years ago
Deal with these relations on the set of real numbers: R₁ = {(a, b) ∈ R² | a &gt; b}, the "greater than" relation, R₂ = {(a, b) ∈
uranmaximum [27]

Answer:

a) R1ºR1 = R1

b) R1ºR2 = R1

c) R1ºR3 = \{ (a,b) \in R^2 \}

d) R1ºR4 = \{ (a,b) \in R^2 \}

e) R1ºR5 = R1

f) R1ºR6 = \{ (a,b) \in R^2 \}

g) R2ºR3 = \{ (a,b) \in R^2 \}

h) R3ºR3 = R3

Step-by-step explanation:

R1ºR1

(<em>a,c</em>) is in R1ºR1 if there exists <em>b</em> such that (<em>a,b</em>) is in R1 and (<em>b,c</em>) is in R1. This means that a > b, and b > c. That can only happen if a > c. Therefore R1ºR1 = R1

R1ºR2  

This case is similar to the previous one. (<em>a,c</em>) is in R1ºR2 if there exists <em>b</em> such that (<em>a,b</em>) is in R2 and (<em>b,c</em>) is in R1. This means that a ≥ b, and b > c. That can only happen if a > c. Hence R1ºR2 = R1

R1ºR3

(a,c) is in R1ºR3 if there exists b such that a < b and b > c. Independently of which values we use for a and c, there always exist a value of b big enough so that b is bigger than both a and c, fulfilling the conditions. We conclude that any pair of real numbers are related.

R1ºR4

This is similar to the previous one. Independently of the values (a,c) we choose, there is always going to be a value b big enough such that a ≤ b and b > c. As a result any pair of real numbers are related.

R1ºR5

If a and c are related, then there exists b such that (a,b) is in R5 and (b,c) is in R1. Because of how R5 is defined, b must be equal to a. Therefore, (a,c) is in R1. This proves that R1ºR5 = R1

R1ºR6

The relation R6 is less restrictive than the relation R3, if we find 2 numbers, one smaller than the other, in particular we find 2 different numbers. If we had 2 numbers a and c, we can find a number b big enough such that a<b and b >c. In particular, b is different from a, so (a,b) is in R6 and (b,c) is in R1, which implies that (a,c) is in R1ºR6. Since we took 2 arbitrary numbers, then any pair of real numbers are related.

R2ºR3

This is similar to the case R1ºR3, only with the difference that we can take b to be equal to a as long as it is bigger than c. We conclude that any pair of real numbers are related.

R3ºR3

If a and c are real numbers such that there exist b fulfilling the relations a < b and b < c, then necessarily a < c. If a < c, then we can use any number in between as our b. Therefore R3ºR3 = R3

I hope you find this answer useful!

5 0
2 years ago
Consider the probability distribution of x, where x is the number of job applications completed by a college senior through the
Oksi-84 [34.3K]
The expected number out of 1000 selected college seniors that completed 1 job application through the career centers is given by 0.011 x 1000 = 11 which is close to 14.

The expected number out of 1000 selected college seniors that completed 2 job application through the career centers is given by 0.115 x 1000 = 115 which is far away from 15.

The expected number out of 1000 selected college seniors that completed 3 job application through the career centers is given by 0.123 x 1000 = 123 which is close to 130.

Therefore, the result that would be suprising is "15 seniors completed 2 job applications through the career center."
3 0
2 years ago
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