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dybincka [34]
2 years ago
12

A manager associated each employee's name with a number on one ball in a container, then drew balls without looking to select a

sample of 555 employees. what type of sampling is this?
Mathematics
2 answers:
RUDIKE [14]2 years ago
7 0
Answer: This type of sampling is Simple Random Sampling
igor_vitrenko [27]2 years ago
6 0

Answer: Simple random sample

Step-by-step explanation:

  • A sample of a statistical population in which each participant of the sample has an equal probability of being chosen is called a simple random sample.

The given statement : A manager associated each employee's name with a number on one ball in a container, then drew balls without looking to select a sample of 555 employees.

Here the probability of each employee has equal chances of being selected.

Hence, this is a simple random sample.

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On Monday Headley paid $1.70 for two of coffee and one doughnut, including the tip. On Tuesday he paid $1.65 for two doughnuts a
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Answer:

i dont wanna say

Step-by-step explanation:

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2 years ago
Is the equation x9 – 5x3 + 6 = 0 quadratic in form? Explain why or why not.
podryga [215]

Answer:

NOO

Step-by-step explanation:

In order for an equation to be quadratic, the highest degree that is needed is two. The highest exponent provided is 3 therefore no it is not a quadratic function

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2 years ago
Read 2 more answers
The following histogram represents the distribution of acceptance rates (percent accepted) among 25 business schools in 2004. In
Mila [183]

Answer:

  • <u><em>Option b. just below 30%</em></u>

<u><em></em></u>

Explanation:

Please, see attached the <em>histogram that represents the distribution of acceptance rates (percent accepted) among 25 business schools in 2004. </em>

<em />

The<em> median</em> is the value that separates the lower 50% from the upper 50% of the data.

Since there are 25 business schools, the middle value is the number 13.

The height of each bar is the<em> frequency</em> or number of business school for that acceptace rate:

  • The first bar has frequency of 1 school
  • The second bar has frequency of 3 schools: cummulative frequency: 1+3=4.
  • The third bar has frequency 5 schools: cummulative frequency 4 + 5 = 9.
  • The fourth bar has frequency 3 schools: cummulative frequency: 9+3=12.

Then, the 13th value is on the next bar, the fifth bar.

The fifth bar has acceptance rates 25  ≤ rate < 30.

That means that the median acceptance rate is greater than or equal to 25 and less than 30.

Thus, the choice is the option <em>b. just below 30%.</em>

3 0
1 year ago
Each ? below represents a factor between 1 and 9
bearhunter [10]
Where is it? I can’t help you without it.
7 0
2 years ago
A cone without a base is made from a half-circle of radius 10 cm. Determine the volume of the cone. Explain your reasoning.
DochEvi [55]

Answer:

  125π√3/3 cm³ ≈ 226.72 cm³

Step-by-step explanation:

The length of the circular edge of the half-circle is ...

  (1/2)C = (1/2)(2πr) = πr = 10π . . . . cm

This is the circumference of the circular edge of the cone, so the radius of the cone is found from ...

  C = 2πr

  10π = 2πr . . . . fill in the numbers; next, solve for r

  r = 5 . . . . cm

The slant height of the cone is the original radius, 10 cm, so the height of the cone from base to apex is found from the Pythagorean theorem.

  (10 cm)² = h² + r²

  h = √((10 cm)² -(5 cm)²) = 5√3 cm

And the cone's volume is ...

  V = 1/3·πr²h = (1/3)π(5 cm)²(5√3 cm)

  V = 125π√3/3 cm³ ≈ 226.72 cm³

5 0
1 year ago
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